What will be the East number which when divided by 16 18 20 and 2 leaves 4 as remainder in each case but when divided by 7 leaves no remainder?

Solution :- 1444 is also not divisible by 7. So, for the value of x = 4, the required number comes 2884. remainder 4 in each case but exactly divisible by 7. Answer.

What is the smallest number which when divided by 16 20 and 25 leaves remainder 7/11 and 16?

Step-by-step explanation: We observe that 9 is the common number.

What is the least common multiple of 16 18 and 20?

The least common multiple of 16, 18, 20 and 24 is 720.

What is the least number which when divided by 16 18 20 and 25?

Correct Option: D Required number = 3600 × 5 + 4 = 18004 , which is exactly divisible by 7.

Which is the smallest no when divided by 18 and 12 leaves remainder 3?

So, The Smallest number is 36 + 3 = 39 which leaves a remainder 3 when divided by 12 and 18.

Which is the least number which when divided by 12 16 36 and 18 leaves a remainder 3 in each case?

What are the LCM of 16 and 18?

144
The LCM of 16 and 18 is 144. To find the LCM (least common multiple) of 16 and 18, we need to find the multiples of 16 and 18 (multiples of 16 = 16, 32, 48, 64 . . . . 144; multiples of 18 = 18, 36, 54, 72 . . . .

What is the LCM of 16 20 and 80?

Answer: LCM of 16, 20, 80 is 80.

What is the LCM of 16 18 20 20 25?

To satisfy first condition, we need to compute LCM of 16, 18, 20 and 25. LCM of these numbers is 3600. So, when the number is divided by 3600, the remainder should be 4.

What is the least possible positive integer that can divide 2884?

When we divide 2884 by any of 12, 16, 18 or 30, we get the remainder as 4 and 7 completely divides 2884. This is the least possible positive integer. Therefore, the required answer is 2884. 720×3+4 = 2164……”

Which number is completely divisible by 12 16 18 18 and 30?

Let the least number be “N”. Now N when divided by 12, 16, 18 and 30 leaves remainder 4 in each case. So, we can say (N-4) is completely divisible by 12, 16, 18 and 30. But N should be completely divisible by 7.

What is the least value of (N-4) with k = 4?

So, we can say (N-4) is completely divisible by 12, 16, 18 and 30. But N should be completely divisible by 7. Thus, general form of N can be taken as: Now, for k = 4, N = 2884 which is completely divisible by 7. Thus, the least value of N is 2884. (Answer) The answer is 2884 . 8 clever moves when you have $1,000 in the bank.