How do you print a first n even number?

Step by step descriptive logic to print even numbers from 1 to n without using if statement.

1. Input upper limit to print even number from user.
2. Run a loop from first even number i.e. 2 (in this case), that goes till n and increment the loop counter by 2 in each iteration.
3. Finally inside loop body print the value of i .

How do you print natural numbers using recursion?

Inside display() function We check if number is not zero, in that case we call the same function display() recursively and pass (num-1) to it. In the else block we write the base condition, that is, return the control back to the calling function if num is 0. This prints the natural numbers from 1 to user input limit.

How do you print first n numbers in Python?

1. # Python program to print numbers from n to 1.
2. number = int ( input ( “Please Enter any Number: ” )) i = number.
3. while ( i > = 1 ):
4. print (i, end = ‘ ‘ ) i = i – 1.

How do you find the sum of the first n even numbers in Python?

First, we declare one variable ” sum ” with value 0, and then we are going to use this variable to store sum of all even numbers between 1 to N. Now after taking input (N) from user, we have to check if the current variable “i” is even or not inside the loop .

What is the first n natural numbers?

As we know natural numbers contain all the positive numbers starting from 1, 2, 3, to n numbers or infinity. For example, suppose when we calculate the sum of the first 25 numbers. That means we start adding the numbers from 1 to the given number 25, and the process is called the sum of the first N natural number.

How do you print the sum of n numbers in Python?

See this example:

1. num = int(input(“Enter a number: “))
2. if num < 0:
3. print(“Enter a positive number”)
4. else:
5. sum = 0.
6. # use while loop to iterate un till zero.
7. while(num > 0):
8. sum += num.

How to print the first n natural numbers in Python?

To print the first N natural number we only have to run one single loop from 1 to N. After taking input (num) from user start one loop from 1 to num, and then inside the loop simply print the current variable “i”. See also: Calculate sum of first N natural numbers

How to print the first n natural number in C++?

To print the first N natural number we only have to run one single loop from 1 to N. After taking input (num) from user start one loop from 1 to num, and then inside the loop simply print the current variable “i”. You must be logged in to post a comment.

How to print natural numbers from 1 to n using while loop?

/* C Program to Print Natural Numbers from 1 to N using While Loop */ #include int main() { int Number, i = 1; printf(“\ Please Enter any Integer Value : “); scanf(“\%d”, &Number); printf(“\ List of Natural Numbers from 1 to \%d are \ “, Number); while(i <= Number) { printf(” \%d \”, i); i++; } return 0; }

How to print all natural numbers in given range using recursive function?

Finally the function should print all natural numbers in given range returning nothing i.e. void. Function declaration to print all natural numbers in given range should look like void printNaturalNumbers (int lowerLimit, int upperLimit); Base condition of recursive function to print natural numbers is loweLimit < upperLimit.