How many ways can a committee of 5 be chosen from 9 people?

How many ways can a committee of 5 be chosen from 9 people?

By multiplication rule, a committee of 5 people out of 9 people can be chosen in 9*8*7*6*5=3024 ways.

How many ways can a professor choose 5 students from a class of 15?

3003 ways
So, there are 3003 ways of picking 5 people from a group of 15. Note that the combination formula can be noted by _nCr . It is this way that you can enter it onto a graphing calculator.

How many possible groups can be made such that there is at least one student with the teacher in the photo?

Answer: The number of possible groups can be made such that there is at least one student with the teacher in the photo is 4 groups.

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How many different ways can you have 1st 2nd 3rd and 4th in a race with 10 runners?

There are 720 different outcomes possible in the race.

How many ways can a committee of 5 be formed from?

There are 252 ways to select a committee of five members from a group of 10 people.

How many ways can we select a committee of five persons?

How many teachers are needed to form a committee?

There are a total of 10 persons (6 teachers + 4 students) from which a committee of 5 is to be formed. This can be done in 10C5 ways. The number of ways that a committee can be formed with no students in it is to select 5 teachers out of the pool of 6 teachers available.

How many committee members do I need to choose from 7?

For all committees that has John onboard, you need to choose 3 more, but you are choosing from a group of 7 as Barbara cannot be on the same committee. So in that scenario you have (7 3) ways of doing it. The same applies if Barbara is to be on the committee and John excluded. So, overall, the total number of ways to do this is:

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How many ways in which 4 people can be chosen?

There are 4 × 3 × 2 ×1 ways in which 4 people can be chosen. 9 × 8 × 7 × 6 × 5 4 × 3 × 2 × 1 = 126 different committees.

How many committees are there in the first person?

There are 9 different choices for the first person. There are 8 different choices for the second person. There are 7 different choices for the third person. There are 6 different choices for the fourth person. This gives 9 ×8 ×7 ×6 different committees, however this will include the same combinations of people.