How many words of 5 letters can be formed of the letters in the word MATHEMATICS?

442 words can be made from the letters in the word mathematics.

How many words can be formed with the letters of the MATHEMATICS by rearranging them?

The word MATHEMATICS consists of 2 M’s, 2 A’s, 2 T’s, 1 H, 1 E, 1 I, 1 C and 1 S. Therefore, a total of 4989600 words can be formed using all the letters of the word MATHEMATICS.

How many 3 letter words can be formed using the letters of MATHEMATICS?

\) # of ways). Answer: 2454.

How many 4 letter words can be formed using the letters?

Therefore, the number of four-letter words that can be formed where the letter R comes at most once, is 840. Case 2: The letter R is repeated in the 4 places.

How many words can be formed combination?

Hence, the answer is 462.

How many words can be formed using letters of Delhi?

The word ‘DELHI’ contains 5 different letters. Required number of words = Number of arrangements of 5 letters, taken all at a time = 5P5 = 5 ! = (5 *4 *3 *2 *1) = 120. In how many different ways can the letters of the word ‘RUMOUR’ be arranged?

How many words can be formed out of 5 different consonants and 4 different vowels if each word is to contain 3 consonants and 2 vowels?

7200. Hint: The number of ways a word can form from $5$ consonants by using $3$ consonants $ = $ ${}^5{C_3}$ and from $4$ vowels by using $2$ vowels $ = $${}^4{C_2}$, hence the number of words can be $ = {}^5{C_3} \times {}^4{C_2} \times {}^5{P_5}$. Use this to find the no.

How many 5 letter words can be formed if repetitions are allowed?

If repetition is allowed, the number of words we can form = 4*4*4*4*4 = 1024. (This is because, when repetition is allowed, we can put any of the four unique alphabets at each of the five positions.) If repetition is not allowed, the number of words we can form = 5!/2! = 60.

How many words can be formed by using the letter combination?

How many letters are in a 5-letter word?

To form 5 letter words in which two letters alike are together, there are possibilities as follows: the 5-letter word contains only single letters: ( 6 5) × 5! the 5-letter word contains 1 double letters and 3 single letters: ( 4 1) × ( 5 3) × 4!

How many words can be formed from 5 letters of independent?

Therefore total no. Of selection =6C5 + 3C1*5C3 + 2C1*5C2+2C1*2C1+3C2*4C1= Since there are no constraints related to repetition or other. So, you can have “55440” words of 5 letters from the letters of the word INDEPENDENT.

How many possible permutations of 4 letters are there?

That’s three possibilities. Next, we find all distinct permutations of our four letters. There is a letter that appears twice, and two other letters that each appear once. To count these permutations, we use the multinomial coefficient $\\binom{4}{2,1,1} = \\frac{4!}{2!1!1!} = 12$.