How do you tell if an equation is factored completely?

How do you tell if an equation is factored completely?

Another way is to look at each element inside the parentheses. In this case, t^2 and 12 are the two elements. You ask yourself, “Do these two elements share a common factor?” If the answer is yes, then you have not completely factored the expression, but if the answer is no, then you have.

What are the solutions to the equation x2 49?

Two solutions were found : x = 7. x = -7.

Is x2 49 a prime polynomial?

The polynomial x2−49 x 2 – 49 is not prime because the discriminant is a perfect square number.

What are the factor of 49?

The factors of 49 are 1, 7, 49 and its negative factors are -1, -7, -49.

How do you Factorise quadratics?

In order to factorise a quadratic algebraic expression in the form ax2 + bx + c into double brackets:

  1. Multiply the end numbers together ( a and c ) then write out the factor pairs of this new number in order.
  2. We need a pair of factors that + to give the middle number ( b ) and ✕ to give this new number.
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How do you factor 49 49 using difference of squares?

Rewrite 49 49 as 72 7 2. Since both terms are perfect squares, factor using the difference of squares formula, a2 −b2 = (a+b)(a−b) a 2 – b 2 = ( a + b) ( a – b) where a = x a = x and b = 7 b = 7.

What can I do with the factoring calculator?

The Factoring Calculator transforms complex expressions into a product of simpler factors. It can factor expressions with polynomials involving any number of vaiables as well as more complex functions. Click the blue arrow to submit and see the result!

How do you factor x^2+5x+4?

If you are factoring a quadratic like x^2+5x+4 you want to find two numbers that. Add up to 5. Multiply together to get 4. Since 1 and 4 add up to 5 and multiply together to get 4, we can factor it like: (x+1) (x+4)

How do you factor in Algebra 1?

Algebra. Factoring Calculator. Step 1: Enter the expression you want to factor in the editor. The Factoring Calculator transforms complex expressions into a product of simpler factors. It can factor expressions with polynomials involving any number of vaiables as well as more complex functions.

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