What is the sum of first 100 terms?

5050
Clearly, it is an Arithmetic Progression whose first term = 1, last term = 100 and number of terms = 100. Therefore, the sum of first 100 natural numbers is 5050.

How do you find the sum of 100?

100 is 5050. Therefore, the sum of first 100 natural numbers = 5050.

How do you find the sum of 100 numbers?

The sum of the numbers 1-100 would be equal to the number of pairs (50) multiplied by the sum of each pair (101), or 50 x 101 = 5,050.

What is the sum of the numbers between 1 and 100?

Since half of the numbers between 1 and 100 are odd, the number of terms in the sequence is 50. So, the average of the first and last term is 50, since (1 + 99)/2 = 50. Multiplying the average by the number of terms, you get 50 x 50 = 2500. So the sum of this sequence is 2,500.

How do you find the sum of the first n terms?

Suppose a sequence of numbers is arithmetic (that is, it increases or decreases by a constant amount each term), and you want to find the sum of the first n terms. Denote this partial sum by S n .

How do you find the sum of a series without adding?

If a series is arithmetic the sum of the first n terms, denoted S n , there are ways to find its sum without actually adding all of the terms. where n is the number of terms, a 1 is the first term and a n is the last term. The series 3 + 6 + 9 + 12 + ⋯ + 30 can be expressed as sigma notation ∑ n = 1 10 3 n .

How do you find the sum of a sequence of numbers?

Suppose a sequence of numbers is arithmetic (that is, it increases or decreases by a constant amount each term), and you want to find the sum of the first n terms. Denote this partial sum by S n . Then S n = n ( a 1   +   a n ) 2 ,