What is the molecular configuration of H2?

What is the molecular configuration of H2?

=》Electronic configuration of H2 molecule is 1s^1.

What is the molecular electronic configuration of H2 minus?

(σ1s)3.

What is molecular electronic configuration?

In atomic physics and quantum chemistry, the electron configuration is the distribution of electrons of an atom or molecule (or other physical structure) in atomic or molecular orbitals. This is also useful for describing the chemical bonds that hold atoms together.

What is electronic configuration of c2?

Sigma 1s2 sigma1 1s*2 sigma2s2 sigma 2s*2 pi 2pz2 (assuming intermolecular axis be z) nd pi2py 1 nd pi2px1.

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What is the electronic configuration of oxygen?

[He] 2s² 2p⁴
Oxygen/Electron configuration

What is the bond order of H2 negative?

zero
So, the bond order is zero.

What is the electron configuration of fluorine?

[He] 2s2 2p5
Fluorine/Electron configuration

What is the electronic configuration of the H2 molecule?

=》Electronic configuration of H2 molecule is 1s^1. =》Bond order of H2 molecule is 1/2. =》It is paramagnetic. Bond order=1/2 [number of bonding electrons -number of antibonding electrons]

What is the bond order of H2+2 ion?

For H atom, it would just be 1s1. For H2 molecule, it would be (σ1s)2. For H− 2 ion, it would be (σ1s)2(σ* 1s)1. For H2− 2 ion, it would be (σ1s)2(σ* 1s)2. The Bond Order, then, is the number of bonding electrons minus the number of antibonding electrons, the total divided by 2.

How many molecular orbitals are there in He2?

Atomic orbitals available for making Molecular Orbitals are 1s from each Helium. And total number of electrons available are 4. It means 2 electrons are in bonding molecular orbitals and 2 are in antibonding molecular orbitals . Since the bond order is zero so that He2 molecule does not exist.

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What is the electronic configuration of the molecular electronic co-compound?

> The molecular electronic co… molecule is formed by the combination of H and H − atoms. Therefore, electronic configuration is 1s2 ∗1s1. Was this answer helpful?