What is the range of a if a sin 2x Cos 4x for all real X?

Thus 3/4 ≤ A ≤ 1 .

What is the maximum value of sin square x cos Square X?

Without going to the maxima and minima analysis we know that the value of cos(x) varies from -1 to 1 throughout R and sin(x) is increasing in the interval [-π/2,π/2] which is a superset of [-1,1]. So we can conclude that the maximum value of sin(cos(x)) is sin(1) and minimum value is sin(-1).

What is the least value of Cos Square x sec square X?

∴ Least value of the given function is 2.

What is the range of cos squared?

The upper bound of the range for cosine is found by substituting the positive magnitude of the coefficient into the equation. The range is −1≤y≤1 – 1 ≤ y ≤ 1 .

How do you find the squared value of sin x – cos x?

The squared result can be obtained by squaring both sides of either 1 = cos x – sin x or 1 = sin x – cos x. Therefore we have merged the solutions of two distinct equations when squaring both sides. This explains why some values of n do not satisfy our original equation. They represent the set of answers for 1 = sin x – cos x.

What is the minimum and maximum value of sin sin x?

Minimum and maximum value of Sin Sin x is. Do not exist-1, 1; Sin -1 , Sin +1 – Sin 1 , Sin 1; We know that, -1 ≤ Sin nx ≤ 1 = Sin (-1) ≤ Sin x ≤ Sin (1) = – Sin 1 ≤ Sin x ≤ Sin 1 ; [Sin(-θ) is same as – Sin θ ] Therefore, Minimum value is –Sin 1 and maximum is Sin 1 ( correct answer D) The key to success is Practice!

What are Sinsin and cos formulas?

Sin and Cos are basic trigonometric functions which tell about the shape of a right triangle, so the Sin Cos formulas are the basic ones in trigonometry. These formulas help in giving a name to each side of the right triangle and these are also used in trigonometric formulas for class 11. Let’s learn the basic sin and cos formulas.

What is the value of sin 2 θ + cos2 θ?

We know that sin 2 θ + cos 2 θ = 1 (identitiy#1) (sin2 θ + cos2 θ) + sec 2 θ + cosec 2 θ + tan 2 θ + cot 2 θ = (1) + sec 2 θ + cosec 2 θ + tan 2 θ + cot 2 θ Using A.M ≥ G.M logic for tan 2 θ + cot 2 θ we get , = 1 + 2 + sec 2 θ + cosec 2 θ