Table of Contents
- 1 How many grams of hydrogen and oxygen are produced when 9g of water is decomposed?
- 2 How many grams of water are made when 8.0 grams of oxygen reacts with hydrogen gas 2h2 O2 2h2o?
- 3 What is the mass of 0.5 mole of hydrogen atom?
- 4 What is the amount of water produced when 8g of hydrogen is reacted with 32g of oxygen *?
- 5 How many grams of hydrogen gas react with 32 grams oxygen?
- 6 Why is 4g of oxygen gas insufficient for making water?
How many grams of hydrogen and oxygen are produced when 9g of water is decomposed?
In a compound such as water, the ratio of the mass of hydrogen to the mass of oxygen is always 1:8, whatever the source of water. Thus, if 9 g of water is decomposed, 1 g of hydrogen and 8 g of oxygen are always obtained.
How many grams of water are made when 8.0 grams of oxygen reacts with hydrogen gas 2h2 O2 2h2o?
So 8 g of oxygen will react with 1 g of hydrogen to produce 9 g of water.
What is the amount of water produced when 8g of hydrogen is reacted with 32g of oxygen * 0.5 mole 2 moles 3 moles 1 moles?
The molecular masses of hydrogen, oxygen and water are 2 g/mole, 32 g/mole and 18 g/mole respectively. 2×2=4 g of hydrogen reacts with 1×32=32 g of oxygen to form 2×18=36 g of water. =9 g of water. 9 grams of water can be produced when 8 g of hydrogen reacts with 8 g oxygen.
How many grams of water can be produced by the combination of 8 grams of oxygen and 8 grams of hydrogen?
9 gram
Complete answer: Hence, with 8 grams of both hydrogen and oxygen, the mass of water produced is 9 gram.
What is the mass of 0.5 mole of hydrogen atom?
therefore 0.5 mole = 1/2 grams = 0.5 grams.
What is the amount of water produced when 8g of hydrogen is reacted with 32g of oxygen *?
What is the amount of water produced when 8g of hydrogen is reacted with 32g of oxygen? Clarification: The chemical equation of water formation is 2H2 + O2 → 2H2O. Though we have 8g of hydrogen, here oxygen is the limiting reagent. So the only 4g of hydrogen can be used to produce water i.e. 36g of water.
What mass of water is formed from 8g of hydrogen gas?
2g of H₂ = 1 mole, therefore, 8g of H₂ = x mole. this implies that 4 moles of hydrogen is present. This implies that the number of moles of water formed = 4 moles.
How do you find the ratio of a Class 9 mass?
How to Calculate Mass Ratio
- Step 2: Determine the Mass of Each Individual Element Present.
- Step 3: Determine the Molar Mass of the Compound.
- Step 4: Divide the Mass of Each Element Present by the Molar Mass.
How many grams of hydrogen gas react with 32 grams oxygen?
4 grams of hydrogen gas reacts with 32 grams of oxygen gas to yield 36 grams of water. Oxygen gas is insufficient since it is only 4 grams. This means that all oxygen gas will react to a proportionate amount of hydrogen to form water.
Why is 4g of oxygen gas insufficient for making water?
Oxygen gas is insufficient since it is only 4 grams. This means that all oxygen gas will react to a proportionate amount of hydrogen to form water. 4 grams of oxygen is only 4/32 moles so only 4/32 * 2 moles of hydrogen gas will react to produce 4/32 * 2 moles of water.
How much oxygen is needed to make 90 grams of water?
90 grams since Oxygen is 16 times heavier than Hydrogen and the formula of water is H2O you have twice as many hydrogen atoms than oxygen atoms, so you would need 8 times the weight of Hydrogen which is 10 x 8 or 80 grams added to the 10 grams of Hydrogen to produce the 90 grams of water. 2H2+O2————->2H2O.
How many grams of water are in 8 grams of hydrogen?
With 8x hydrogen, you get 8x water, 72g. You wil also have 8g oxygen left over. If your first part proposed, 1 g of hydrogen and 800 g of oxygen, it would still form only 9 g of water. Does DHT shampoo work for hairloss?