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What is the mole fraction of H2SO4 in a solution containing 98\% H2SO4 by mass?
of moles of H2SO4 = (98g)/(98g/mol) = 1 mol, no. of moles of H2O = (2g/18g/mol) = 0.11 mol. Thus mole fraction of H2SO4 is 0.9.
What is the mole fraction of H2SO4 in a solution containing the percentage of sulfuric acid and water?
Explanation: If the mole fraction of water is 0.85, the mole fraction of sulfuric acid is 0.15.
How many moles of H2SO4 are there in 98 g of H2SO4?
Therefore 98 gm(1mole) of H2SO4 will contain one mole of H2 gas. And two moles of Hydrogen atoms.
What concentration is 98\% sulfuric acid?
Dilutions to Make a 1 Molar Solution
| Concentrated Reagents | Density | Molarity (M) |
|---|---|---|
| Perchloric acid 70\% | 1.67 | 11.6 |
| Orthophosphoric acid 85\% | 1.7 | 15.2 |
| Sodium hydroxide 47\% | 1.5 | 17.6 |
| Sulfuric acid 98\% | 1.84 | 18.4 |
What is the mole fraction of H2SO4?
98\% by weight H2SO4 means 98gm of H2SO4 is present in 100 gm of solution. The solution consists of solvent and solute. Here, since 98gm is of H2SO4 then 2gm is water ( if nothing is given then assume by default water as one of the solvent or solute as per the requirement ). So, 98gm H2SO4 is = 1mol.
How do you find the mole fraction of H2SO4?
- Answer:
- ==> 0.166.
- ==>gram molecular weight of H2SO4 = 98g.
- ==>Moles of H2SO4 = (2080-1000)/98 = 11.02.
- ==> moles( 1 litre = 1000g and density of.
- ==>moles of water = 1000/18 = 55.56.
- ==>Mole fraction = 11.02/11.02+55.56= 0.166.
How many moles are there in 98 g of Sulphuric acid?
Answer: 1 mole. total= 98. Put value in formula.
What is the volume of 98\% by mass of H2SO4?
100 The weight of sulfuric acid = 28.8 x 98 x 98 = 2880 Density – Mass Volume = 1.8 g/ml. Mass Hence, volume of the sulfuric acid solution is a density 2880 g ; = 1600 ml = 1.6 L 1.8 g/ml 206 EAST.
How do you calculate the normality of 98 Sulphuric acid?
Use this formula: mol. weight / basicity (or n factor), giving you 49.03. Then, find normality using the weight of solute x 1000 / equivalent weight x volume of solution in ml, which would ultimately give you 12.26 grams. Therefore, you have to use 12.26 g of H2SO4 to prepare your 10 N concentrated H2SO4 solution.
What is mole fraction class 12?
Class 12 Chemistry Solutions. Mole fraction. Mole fraction. Mole fraction can be defined as the ratio of number of moles of the component in the solution to the total number of moles of all components in the solution.
What is the mole fraction of H2SO4 in the 98\% solution?
98\% solution means 98g H2SO4 in 100g solution. Therefore it contains 1 mole of H2SO4 and (2/18) moles of water. Mole fraction of H2SO4 = 1/ (1+ 2/18) = 18/20 = 0.9 98\% aqueous H2SO4 solution by mass contains 98g of H2SO4 and 2g of water.
What is the molal concentration of sulfuric acid in water?
The molal concentration is 9.8 mol/kg. If the mole fraction of water is 0.85, the mole fraction of sulfuric acid is 0.15.
How do you prepare concentrated sulphuric acid from H2SO4?
As we know concentrated sulphuric acid is 96\% in H2SO4 by weight and the remaining 4\% water. So to prepare 1 litre (1000 mL) of the 20\% acid, you have to take 2o x 1000/96 mL of conc. H2SO4 and dilute it to 1 L with water.
How many moles of HCl are in a 64g solution?
The molar mass of HCl = 36.5 g/mol, so 100 g of solution contain 0.986 mol HCl. The difference to 100 g, 64 g is water, 64 / 18 = 3.556 mol. That makes a total number of moles of 4.542 and the mole fraction of HCl in the solution is 0.986 / 4.542 = 0.217 (no dimension).