What is the equation of a circle tangent to the y-axis?

Correct answer: The formula for the equation of a circle is (x – h)2+ (y – k)2 = r2, where (h, k) represents the coordinates of the center of the circle, and r represents the radius of the circle.

How do you find the equation of a circle with the center and tangent to the y-axis?

The center can be translated by subtracting from the x and y values accordingly, so in this case our equation would be (x−3)2+(y+7)2=r2 , because the center of our circle is at (3,−7) . Now, as for the radius, and the circle being tangent to the y-axis. This means it has to touch the y -axis at some point.

How many circles can pass through two points?

We can draw infinitely many circles passing through two given points. Starting from the two points as a diameter, we can draw a circle. As the circle is moving up it becomes a chord to the next circle with a bigger diameter.

How do you find the points of a tangent to a circle?

Hi A point of contact between a tangent and a circle is the only point touching the circle by this line, The point can be found either by : equating the equations; The line : y = mx +c The circle : (x-a)^2 + (y_b)^2 = r^2 The result will be the value of {x}which can be substituted in the equation of the line to find …

What is the equation for a circle passing through two points?

Equation of a Circle Through Two Points and a Line Passing Through its Center. Consider the general equation a circle is given by. x 2 + y 2 + 2 g x + 2 f y + c = 0. If the given circle is passing through two points, say A ( x 1, y 1) and B ( x 2, y 2), then these points must satisfy the general equation of a circle.

How do you find the general equation of a circle?

If the given circle is passing through two points, say A ( x 1, y 1) and B ( x 2, y 2), then these points must satisfy the general equation of a circle. Now put these two points in the given equation of a circle, i.e.: Also, the given straight line a x + b y + c 1 = 0 passes through the center ( – g, – f) of the circle.

How to find the slope of the line passing through the points?

Let us the formula to calculate the slope of the line passing through the points (2,5) ( 2, 5) and (−5,1) ( − 5, 1); Subtract the second coordinates and first coordinates, this gives us yB − yA = 1− 5 = −4 y B − y A = 1 − 5 = − 4 and xB − xA = −5− 2 = −7 x B − x A = − 5 − 2 = − 7;

Is it possible to draw a circle through a set of points?

No solution means that points are co-linear, and it is impossible to draw a circle through them.