What is the equation of a circle with Centre at 2/3 and a radius of 4?

The equation of the circle with center (2, -3) and a radius of 4 is x2 + y2 – 4x + 6y = 3.

How do you find the equation of a circle given the center and a point?

Starts here3:26Write the equation of a circle given the center and a point it passes
throughYouTubeStart of suggested clipEnd of suggested clip60 second suggested clipAnd that equation is X minus H squared plus y minus K squared equals R squared.MoreAnd that equation is X minus H squared plus y minus K squared equals R squared.

What is the equation of a circle with center (- 2 3?

⇒(x+2)2+(y+3)2=9 is the circle’s equation.

How do you find the equation of a circle given the center and a tangent line?

Starts here3:33Find the standard equation of a circle given a center and a tangent lineYouTubeStart of suggested clipEnd of suggested clip53 second suggested clipX minus H quantity squared. Plus y minus K quantity squared equals R squared. The equation is X plusMoreX minus H quantity squared. Plus y minus K quantity squared equals R squared. The equation is X plus 3 quantity squared plus y minus 2 quantity squared equals 13.

What is the equation of a circle with center 2?

The equation of a circle with center (h,k) and radius r units is (x−h)2+(y−k)2=r2 .

What is an equation of a circle with center − 2 − 1 and radius 3?

The equation of the circle whose center is (2,1) and radius is 3 is (x – 2)2 + (y – 1)2 = 9.

What is the equation of a circle with Centre 2 3 and radius 3?

Explanation: The eqn. of a circle with centre (h,k) and radius r is given by, (x−h)2+(y−k)2=r2 .

What is the equation of a circle with center?

How do you find the center of a circle with Y=X-4?

It is y+3=x-4 (the slope of this line is 1). The center of the circle should be on the intersection of lines y+3=x-4 (or y=x-7) and x-y=1 (or y= x-1). Lines y=x-7 and y = x-1 are parallel, their intersection does not exist.

What is the radius of the circle perpendicular to 3x-4y+1?

Now you know the radius of the circle, it is 1. The line perpendicular to 3x-4y+1=0 and which passes through (2, 3) is 4x+3y-17=0. The intersection of the two lines is the tangent point of the line and circle at (13/5, 11/5).

What is the equation of circle?

Hence, the equation of circle is x 2+y 2−4x−2y+4=0. Was this answer helpful? A line is at a constant distance c from the origin and meets the coordinates axes in A and B.

How do you find the distance between a circle and a line?

When you say the circle touches that line, it means the line is tangent to it, thus, the distance between the center C and the line [math]5x + 12y – 19 = 0 [/math] is exactly the radius. Something like that. Where a, b, and c are the coefficients of the line (ax + by + c = 0), and x and y are the coordinates of the point.