Is twice as efficient as B and can complete a job 30 days before B in how much they can complete the job together?

Example 5: A person A is twice as efficient as another person B. The person A can complete a job 30 days before B. Answer: Let the efficiency of B = x and thus the efficiency of A = 2x. Since the person A takes 30 days to complete a job, the person B will take 60 days to complete the same job.

Is twice efficient than B?

Since, A completes the same work 12 days earlier than B. Therefore we can write, A completes a work in (x-12) days. Now since it is given in the question that A is twice more efficient than B, so we can say that A takes half of the time that B. Therefore we can say that B completes work in 24 days.

Does 30\% more efficient than B time work together?

A is 30\% more efficient than B. How much time will they, working together, take to complete a job which A alone could have done in 23 days? Explanation: Ratio of times taken by A and B = 100 : 130 = 10 : 13.

Is thrice as good as workman as B?

So, A takes 30 days to do the work. A’s 1 day’s work = 130 B’s 1 day’s work = 190 (A+B’s 1 day’s work = (130+190)=490=245 ∴ A and B together can do the work in days 452=2212. A is thrice as good a workman as B and takes 64 days less than B for doing a job.

Is a twice as efficient as B?

A is twice efficient as B. A and B together do the same work in as much time as C and D can do together. If the ratio of the number of alone working days of C to D is 2:3 and if B worked 16 days more than C then no of days which A worked alone?

How long does it take to complete the same job?

If A does a job in 30 days, B will take 60 days to complete the same job. (Just for the sake of A completing it 30 days before B) So, while A was takng 30 days to complete a job and B was taking 60 days to complete the same job, together they can do it in 20 days.

Can A and B work together to do a job in 20 days?

Treated as a pure algebra problem, the other answers are correct. Let’s solve for the number of days each takes to complete the job. So A does 1/30 of the job per day, and B does 1/60 of the job per day. Together, they do 3/60 per day, which 1/20. So _supposedly_ A and B working together can do the job in 20 days. But there’s a serious fault here.

How many works can be completed in 20 days?

Given that,A is twice efficient and complete its work before 30 days. When you take l.c.m for 30 and 60,you will get 60 which is nothing but the total no. Of works to be done. Thus in 20 days , total of 60 works can be completed when A and B works together.

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