How do I find the next largest number in an array?

Step 1: Declare a stack and push the first array element into the stack. Step 2: Traverse the array and pick the array element one by one. Step 3: If the incoming array element is greater than the top element of the stack, then for the top element in the Stack, the incoming element is the next greater element.

How do you find the next greater number with the same set of digits in Python?

If all the digits are in ascending order from left to right then all we have to do is swap the last two digits. If the digits are not in any order, then in that case we start from the rightmost number to find for the next greater number.

What is next permutation of numbers?

Implement the next permutation, which rearranges numbers into the numerically next greater permutation of numbers for a given array A of size N. If such arrangement is not possible, it must be rearranged as the lowest possible order i.e., sorted in an ascending order.

What is a greater permutation?

The lexicographically next permutation is basically the greater permutation. For example, the next of “ACB” will be “BAC”. In some cases, the lexicographically next permutation is not present, like “BBB” or “DCBA” etc. In C++ we can do it by using a library function called next_permutation().

How do I find the next permutation in lexicographic order in Python?

Next Permutation in Python

1. m := find maximum element index from index i + 1, from A, and from the current element A[i]
2. swap the elements A[i] and A[m]
3. reverse all the elements from i+1 to the end in A.

What will be the most efficient approach to find the largest number in a list of twenty?

See the leftmost digit of the numbers given. The digit with highest left most digit is largest number. If there are more than one numbers with same leftmost digit, Then see the second leftmost digit of these numbers, the number with highest number at second left place will be largest.

How to develop an algorithm for finding the next greater number?

You can now try developing an algorithm yourself. Following is the algorithm for finding the next greater number. I) Traverse the given number from rightmost digit, keep traversing till you find a digit which is smaller than the previously traversed digit.

How to find the next greater number using same digits?

Given a number, find the next greater number using same digits (or by rearranging the digits). For example, if the given number is 1234 then next greater number would be 1243. For the input 1243, next greater number would be 1324.

What is the maximum number that can be obtained using all digits?

Suppose we have a number of n digits. We have to find the maximum number that can be obtained using all digits of digits of that number. So if the number is say 339625, then maximum number can be 965332. From the problem, we can see that we can easily sort the digits in non-increasing order, then print them.

How do you find the smallest number found by the algorithm?

The number found by our algorithm is AyC, where y ∈ B is the smallest digit > x (it must exist due to the way x was chosen, see above), and C is sorted ascending. Assume there is some number (using the same digits) N’ such that AxB < N’ < AyC. N’ must begin with A or else it could not fall between them, so we can write it in the form AzD.