How do you calculate the molality of a NaOH solution?

1. Solution is 40\% NaOH by mass.
2. That is 40g NaOH in 100 g solution.
3. That is 40 g NaOH dissolved in 60 g H2O.
4. Mass of NaOH dissolved in 1000 g H2O = 40g / 60 g *1000 g = 666.7 g NaOH in 1.0kg water.
5. Molar mass NaOH = 40g/mol.
6. Mol NaOH in 666.7g = 666.7g/40 g/mol = 16.67 mol.
7. Solution is 16.67m.

How do you find the molality of a solution with density?

The formula for molality is m = moles of solute / kilograms of solvent. In problem solving involving molality, we sometimes need to use additional formulas to get to the final answer. One formula we need to be aware of is the formula for density, which is d = m / v, where d is density, m is mass and v is volume.

What is the molarity of a 2 g NaOH in 100 ml water?

Detailed Solution 2 grams of NaOH are needed to make 100 ml. of a 0.5 M solution of NaOH. So, mass of NaOH = 0.05*40 = 2 grams.

What will be the molarity m of 20\% w/w NaOH solution if density of solution is 1.2g ML?

⇒ Molarity = 6 M.

What is NaOH molality?

Molality may be defined as the number of moles of the solute to the mass of solvent in kilograms. It is denoted by m. 1m NaOH means 1mole of NaOH is present in 1L of the solution.

How do you calculate molality from molarity and density?

1. Conversion from Molarity to Molality.
2. Problem: Find the molality of 18 M H2SO4.
3. Make an assumption.
4. Assume you have 1 L of solution.
5. Find the total mass of the solution.
6. Multiply 1 L X the density (1.84 g/mL) X 1000 mL/L.
7. Calculate the grams of the solute.
8. 18M means 18 moles of sulfuric acid per one liter of solution.

What is the molarity for NaOH?

The molarity of NaOH is 2.002 x 10 -2 moles x 1000 mL/L / 25.0 mL = 0.801 Molar.

What is the molarity of 20\% NaOH?

0.5 moles
Calculate the molarity of the solution. 20 gr of NaOH correspond to 0.5 moles which are contained in 0.5 liter of solution. In one liter of solution there will be (2)(0.5) = 1 mole and thus the solution is 1 M. 5.

What is the molality of 20 w/w aqueous solution of sodium hydroxide?

A. 4.5 m.

How do you calculate the number of moles of solute in NaOH?

The first step is calculating the number of moles of solute present. If you have dissolved 1 g of NaOH in enough water to make a total of 250 ml of solution, calculate the number of moles of solute present by diving the mass of NaOH by the molecular mass of the compound. The molecular mass of NaOH is 40, so work out 1 ÷ 40 = 0.025.

What is the molar mass of 40\% NaOH in water?

40\% m/m solution of NaOH means 100g water has 40g NaOH So, number of moles of NaOH= 40/molar mass of NaOH =40/40 =1 Molality = number of moles of solute/mass of solvent (in kg) = no. of moles of NaOH/ mass of water = 1/(100×0.001) = 10 molal.

What is the density of 30\% NaOH solution?

An aqueous solution labelled 30\% (w/v) NaOH had a density of 1.20g/ml. What is the molality of the solution? so weight of water = 120–30g = 90g water.

How do you calculate the number of liters in NaOH?

The molecular mass of NaOH is 40, so work out 1 ÷ 40 = 0.025. Next, calculate the number of liters of solution present. In this example, you have 250 ml of solution. Convert to liters by dividing by 1000, because there are 1000 milliliters in one liter.