How do you find the equation of the perpendicular bisector of a line?

Perpendicular bisector will pass through the points A and B i.e. point M. In this case, the perpendicular bisector is eventually a line passing through point M(5,3) and having slope m2=1. Thus the equation of the perpendicular bisector is x−y−2=0.

How do you find the equation of a line perpendicular to the line that passes through the given point?

Perpendicular lines have opposite-reciprocal slopes, so the slope of the line we want to find is 1/2. Plugging in the point given into the equation y = 1/2x + b and solving for b, we get b = 6. Thus, the equation of the line is y = ½x + 6.

How do you tell if a line is perpendicular with an equation?

Perpendicular lines intersect at right angles to one another. To figure out if two equations are perpendicular, take a look at their slopes. The slopes of perpendicular lines are opposite reciprocals of each other.

How do I write the equation of a line?

The equation of a line is typically written as y=mx+b where m is the slope and b is the y-intercept.

How do you work out the equation of a line?

The general equation of a straight line is y = mx + c, where m is the gradient, and y = c is the value where the line cuts the y-axis. This number c is called the intercept on the y-axis. The equation of a straight line with gradient m and intercept c on the y-axis is y = mx + c.

Which line is perpendicular to the equation whose equation is 5y 6 3x?

The line 5y+6=−3x has standard form y=−35x−65 . Hence its gradient (or slope) is −35 . From the theory we know that perpendicular lines have gradients whose product is −1 . So any line with gradient 53 will be perpendicular to the original given line.

Which equation represents a line perpendicular to the line whose equation is y 3x 2?

2 Answers By Expert Tutors So the line perpendicular to y = 3x – 2 has a slope of -1/3. That’s the answer. If they want you to give the answer in the y= mx + b format (slope-intercept) then multiply it out and combine like terms.

What is the equation of the perpendicular bisector with midpoints?

The slope of the perpendicular bisector = -1/slope of the line. Once we find the slope as above, we can find the equation with the slope and the midpoints. Lets find the equation of the AB with midpoints (9/2,10/2) and the slope -2.5. Formula to find the equation: y-y1 = m (x-x1) y-10/2 = -2.5 (x-9/2)

How to find the slope of the perpendicular bisector of PQ?

Now, let’s calculate the slope of the perpendicular bisector (AB) of the line PQ. The slope of the perpendicular bisector = -1/slope of the line. Once we find the slope as above, we can find the equation with the slope and the midpoints. Lets find the equation of the AB with midpoints (9/2,10/2) and the slope -2.5.

How to find the equation of a perpendicular line with two points?

Before you calculate the equation of the perpendicular line, you will need to find the slope of the line that crosses the two points. The equation for finding the slope of a line with two points is m = y 2 − y 1 x 2 − x 1 {\\displaystyle m={\\frac {{y^{2}}-{y^{1}}}{{x^{2}}-{x^{1}}}}} .

How to find the slope of a perpendicular line in slope intercept form?

First, put the equation of the line given into slope-intercept form by solving for y. You get y = -2 x +5, so the slope is –2. Perpendicular lines have opposite-reciprocal slopes, so the slope of the line we want to find is 1/2. Plugging in the point given into the equation y = 1/2 x + b and solving for b, we get b = 6.