Table of Contents
- 1 How do you find the third vertex of an equilateral triangle?
- 2 Is 0 3 and 0 3 are the two vertices of an equilateral triangle find the coordinates of a third vertex?
- 3 Does an equilateral triangle have 2 vertices?
- 4 What is vertices of equilateral triangle?
- 5 How do you find the third vertex of an isosceles triangle?
- 6 What is the third vertex of a triangle if two of its vertices are at 3/1 and 0 2 and the centroid is at the origin?
How do you find the third vertex of an equilateral triangle?
Solving the quadratic equation using the quadratic formula, [-b ± √(b2 – 4ac)]/2a. Hence, the coordinates of the third vertex of the equilateral triangle are ([1 ± √(3)] / 2, [7 ± 5√(3)] / 2). Let the coordinates of the circumcentre of the triangle be (x, y).
Is 0 3 and 0 3 are the two vertices of an equilateral triangle find the coordinates of a third vertex?
Therefore, the coordinates of the third point is ( 3 3 , 0 ) or ( − 3 3 , 0 ) .
How do you find the third vertex when given two vertices?
- The area of a triangle is 5. Two of its vertices are (2,1) and (3,−2). The third vertex lies on y=x+3.
- The area of a triangle is 5 and its two vertices are A(2,1) and B(3,−2). The third vertex lies on y=x+3.
- Two vertices of a triangle are (1,4) and (5,2). If its centroid is (0,−3), find the third vertex.
Does an equilateral triangle have 2 vertices?
Two vertices of an equilateral triangle are (−1,0) and (1,0), and its third vertex lies above the x-axis.
What is vertices of equilateral triangle?
3
Equilateral triangle/Number of vertices
Is 3 and 4/3 are the two vertices of an equilateral triangle find the coordinates of the third vertex?
Third vertex = (x, y) = (0, 3 – 4√3).
How do you find the third vertex of an isosceles triangle?
- Let ΔABC be the isosceles triangle, the third vertex be C(a,b). and A(2,0) and B(2,5)
- Let AC and BC be equal sides of the triangle.
- By distance formula we have, D=(x2−x1)+(y2−y1)
- ∴AB=(2−2)2+(5−0)2 =25 =5.
- Now,
What is the third vertex of a triangle if two of its vertices are at 3/1 and 0 2 and the centroid is at the origin?
Two vertices of ΔABC are B (-3, 1) and C (0, -2) . Therefore, the third vertex of ΔABC is A(3,1) .
How do you find the coordinates of an equilateral triangle?
Find the slope of AB (YA-YB / XA-XB), call it m. Find the perpendicular to that (-1/m) and call it m2. Then compute a segment CD whose length is sin(60) * length(AB), at the slope m2 (there will be two such points, one to each side of AB). ABD is then your equilateral triangle.