How do you find the third vertex of an equilateral triangle?

How do you find the third vertex of an equilateral triangle?

Solving the quadratic equation using the quadratic formula, [-b ± √(b2 – 4ac)]/2a. Hence, the coordinates of the third vertex of the equilateral triangle are ([1 ± √(3)] / 2, [7 ± 5√(3)] / 2). Let the coordinates of the circumcentre of the triangle be (x, y).

Is 0 3 and 0 3 are the two vertices of an equilateral triangle find the coordinates of a third vertex?

Therefore, the coordinates of the third point is ( 3 3 , 0 ) or ( − 3 3 , 0 ) .

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How do you find the third vertex when given two vertices?

  1. The area of a triangle is 5. Two of its vertices are (2,1) and (3,−2). The third vertex lies on y=x+3.
  2. The area of a triangle is 5 and its two vertices are A(2,1) and B(3,−2). The third vertex lies on y=x+3.
  3. Two vertices of a triangle are (1,4) and (5,2). If its centroid is (0,−3), find the third vertex.

Does an equilateral triangle have 2 vertices?

Two vertices of an equilateral triangle are (−1,0) and (1,0), and its third vertex lies above the x-axis.

What is vertices of equilateral triangle?

3
Equilateral triangle/Number of vertices

Is 3 and 4/3 are the two vertices of an equilateral triangle find the coordinates of the third vertex?

Third vertex = (x, y) = (0, 3 – 4√3).

How do you find the third vertex of an isosceles triangle?

  1. Let ΔABC be the isosceles triangle, the third vertex be C(a,b). and A(2,0) and B(2,5)
  2. Let AC and BC be equal sides of the triangle.
  3. By distance formula we have, D=(x2​−x1​)+(y2​−y1​) ​
  4. ∴AB=(2−2)2+(5−0)2 ​=25 ​=5.
  5. Now,
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What is the third vertex of a triangle if two of its vertices are at 3/1 and 0 2 and the centroid is at the origin?

Two vertices of ΔABC are B (-3, 1) and C (0, -2) . Therefore, the third vertex of ΔABC is A(3,1) .

How do you find the coordinates of an equilateral triangle?

Find the slope of AB (YA-YB / XA-XB), call it m. Find the perpendicular to that (-1/m) and call it m2. Then compute a segment CD whose length is sin(60) * length(AB), at the slope m2 (there will be two such points, one to each side of AB). ABD is then your equilateral triangle.