How do you find the third vertices of an equilateral triangle?

Substituting the value of y in equation (1) and equating it to 26. Solving the quadratic equation using the quadratic formula, [-b ± √(b2 – 4ac)]/2a. Hence, the coordinates of the third vertex of the equilateral triangle are ([1 ± √(3)] / 2, [7 ± 5√(3)] / 2).

What is the third coordinate?

In that case the third coordinate may be called height or altitude. The orientation is usually chosen so that the 90 degree angle from the first axis to the second axis looks counter-clockwise when seen from the point (0, 0, 1); a convention that is commonly called the right hand rule.

How do you find the Circumcenter of a triangle whose vertices are given?

Step 1: Draw the perpendicular bisector of any two sides of the given triangle. Step 2: Using a ruler, extend the perpendicular bisectors until they intersect each other. Step 3: Mark the intersecting point as P which will be the circumcenter of the triangle.

How do you find the third vertex of a triangle with two vertices?

1. The area of a triangle is 5. Two of its vertices are (2,1) and (3,−2). The third vertex lies on y=x+3.
2. The area of a triangle is 5 and its two vertices are A(2,1) and B(3,−2). The third vertex lies on y=x+3.
3. Two vertices of a triangle are (1,4) and (5,2). If its centroid is (0,−3), find the third vertex.

How do you find the third vertex of a triangle when given two vertices?

Firstly taking the midpoint \[\left( {0,3} \right)\] be the midpoint of the side AC. Hence the third vertex is \[\left( {1,2} \right)\]. Now we will take the second condition i.e. mid-point \[\left( {0,3} \right)\] is the midpoint of the side BC. Hence the third vertex is \[\left( { – 5,4} \right)\].

How do you find the third vertex of an equilateral triangle?

If two vertices of an equilateral triangle are (0,0) and (3,√3) then find the third vertex. The first thing I did was calculated the distance of the given points and tried to make an equation including the third vertex but instead of being simplified, the term went on being complex.

What are the coordinates of the third vertex of B?

Hence, the coordinates of the third vertex B are (0, 2 √3) or (3, – √3). Is there an error in this question or solution?

How do you find the 3rd vertex of a matrix?

Use complex numbers. Multiply 3 + i 3 by e i π / 3 to get the third vertex. This is because the origin is already one of the vertices. For the clockwise possibility, multiply by the inverse matrix instead i.e. replace 60 with − 60 in the above.

What is the angle from x-axis to 3/3?

If you notice that the angle from the x -axis to ( 3, 3) is 30 °, then you will see that the third vertex must be either on the y -axis or the reflection of ( 3, 3) over the x -axis. (Note that ( 3, 3) is a scalar multiple of ( 3 2, 1 2) .)