How do you prepare K2Cr2O7?

Note:Potassium dichromate can be prepared by chromite ores, by first roasting the ores with sodium carbonate in presence of quick lime. Then treating the sodium chromate, which was obtained as a product of the first reaction, with sulphuric acid, in order to get sodium dichromate.

How do you make a chromium stock solution?

To prepare the stock standard solution, K2Cr2O7 was dried at 150°C for one hour then placed in a desiccator. 8.79 mg of the K2Cr2O7 was dissolved in 100 mL water and 80.4 mL of this solution was diluted to 100 mL in a 100 mL flask, producing a 25 mg/L chromium standard stock solution.

How do you make 0.5 N ferrous ammonium sulphate?

0.5N ferrous ammonium sulphate (Mohr’s salt): Dissolve 392gm of Fe(NH4)2(SO4)2. 6H2O in distilled water. Add 15ml of conc. H2SO4 and make up the volume to 2litre with distilled water.

What is n factor of K2Cr2O7 in basic and neutral medium?

Hence the n-factor is 6.

How do you find the equivalent weight of K2Cr2O7?

Calculate equivalent weight of K2Cr2O7 in acidic medium. = 294 g/mol. Now, putting these values in above formula of equivalent weight: \[Equivalent{\text{ }}weight = \dfrac{{294}}{6} = 49g/eq\]. Hence, the equivalent weight of ${K_2}C{r_2}{O_7}$ in acidic medium will be 49g/eq.

How will you prepare 1000 ppm stock?

To make 1000 ppm P stock solution, dissolve 4.3937 g of dried KH2P04 in deionized H20 then dilute to 1 L. (10 ppm: 1 mL of 1000 ppm stock diluted to 100 mL dH20.

How do you prepare stock solution in ppm?

Use the standard dilution formula in general chemistry, i.e., Volume(1) x Concentration(1) = Volume(2) x Concentration(2). Make sure all your units are the same. Thus, you can either change 1000 ppm to ppb (1000 ppm x 1000 ppb/1ppm) = 1000000 ppb or you can change the ppb needed to ppm.

How do you prepare 1 normal solution of K2Cr2O7?

Inorder to prepare 1 normal solution, we need to dissolve one gram equivalent of K2Cr2O7 i.e. 49.03 grams of it in one litre solution. Normality= (mass of solute×1000)÷ (gram equivalent mass of solute×volume of the solution in ml.). Gram molar mass of KCr2 O7=294.18 gram .

What is the equivalent weight of K2Cr2O7 in grams?

Here oxidation state changed from (2×6 to 2×3, so the change is 6) the equivalent weight of K2Cr2O7 =294.18/6=49.03. Inorder to prepare 1 normal solution, we need to dissolve one gram equivalent of K2Cr2O7 i.e. 49.03 grams of it in one litre solution. Normality= (mass of solute×1000)÷ (gram equivalent mass of solute×volume of the solution in ml.).

How much K2Cr2O7 is equivalent to 1 mL of ethanol?

Or 1 mL of 0.1N solution of K2Cr2O7 would contain 4.9mg of it. Thus we can prove that, 1mL of 0.1N K2Cr2O7 is equivalent to 1.15mg of ethanol. Save up to 80\% on your next printer ink cartridges!

How much KMnO4 is required to dissolve in 1L water?

So for 0.1 N KMnO4 solution, you have to dissolve 3.16g KMnO4 in 1L water. (Usually a little bit excess is taken, say 3.25g, since some crystals of KMnO4 will be remained undissolved that have to be removed by filtration.