How do you reverse a number with zeros in Java?

Simply apply the steps/algorithm discussed and terminate the loop when the number becomes zero.

1. Take the number’s modulo by 10.
2. Multiply the reverse number by 10 and add modulo value into the reverse number.
3. Divide the number by 10.
4. Repeat the above steps until the number becomes zero.

How do you reverse a long number in Java?

Example 1: Reverse a Number using a while loop in Java

1. First, the remainder of the num divided by 10 is stored in the variable digit .
2. After second iteration, digit equals 3, reversed equals 4 * 10 + 3 = 43 and num = 12.
3. After third iteration, digit equals 2, reversed equals 43 * 10 + 2 = 432 and num = 1.

How do you reverse 1000 in Java?

Java program to reverse number

1. import java. util. Scanner;
2. class ReverseNumber {
3. public static void main(String args[]) {
4. int n, reverse = 0;
5. System. out. println(“Enter the number to reverse”);
6. Scanner in = new Scanner(System. in);
7. n = in. nextInt();
8. while( n != 0 ) {

Is there any function to reverse a number in Java?

Integer reverse() Method In Java The java. Integer. reverse() is an inbuilt method in Java and is used to return the reverse order of the bits in the two’s complement binary representation of the specified int value.

How do you reverse a number 100 in Java?

How to Reverse a Number in Java

1. First, we find the remainder of the given number by using the modulo (\%) operator.
2. Multiply the variable reverse by 10 and add the remainder into it.
3. Divide the number by 10.

How do you reverse a number ending in 0?

1. import java. util. *;
2. class reverse{
3. public static void main(String args[]){
4. int n = 6547,r,rev=0;
5. while(n>0){ // the condition in step 4.
6. r = n \% 10; // step 1 from algorithm.
7. rev = rev * 10 + r; // step 2.
8. n = n / 10; // step 3.

How do you reverse a number with leading zeros in C?

I wrote below program but it works only when no leading zeroes in input. int num; cout<<“Enter number “<>num; int rev = 0; int reminder; while(num != 0) { reminder = num \% 10; rev = rev * 10 + reminder; num = num / 10; } cout<<“Reverse = “<; Is there any way to input a number with leading zeroes?

How do you reverse input in Java?

1. import java. util. Scanner;
2. public class ReverseString. {
3. public static void main(String[] args) {
4. System. out. println(“Enter string to reverse:”);
5. Scanner read = new Scanner(System. in); String str = read. nextLine();
6. String reverse = “”;
7. { reverse = reverse + str. charAt(i);
8. }

How do you reverse a number in JavaScript?

How to reverse a number in JavaScript

1. const reversedNum = num => parseFloat(num.
2. function reversedNum(num) { return ( parseFloat( num .
3. let num = -5432100 num.
4. // num = ‘-5432100’ num.
5. // num = [ ‘-‘, ‘5’, ‘4’, ‘3’, ‘2’, ‘1’, ‘0’, ‘0’ ] num.
6. // num = [ ‘0’, ‘0’, ‘1’, ‘2’, ‘3’, ‘4’, ‘5’, ‘-‘ ] num.

How to reverse a number in Java program?

2) Using Rev class object r, call the method reverse (x ) as r.reverse (x), then reverse (x) method starts the execution and calls itself as reverse (num) until num!=0. If you have any doubts or suggestions about Reverse A Number In Java program do leave a comment here.

How to reverse leading zeros in a string?

Leading zeroes are not represented by binary numbers (int, double, etc.) So you’ll probably have to use std::string. Read the input into the string, then call std::reverse()passing the string as input. Share Improve this answer

What is the reverse number of 4321 in Java?

Now the value of the number and reverse variable is 12 and 43, respectively. Now the value of the number and reverse variable is 1 and 432, respectively. Now the variable number become 0. Hence, we get the reverse number 4321. Let’s implement the above logic in a Java program.

How do you reverse a recursive function in Java?

1) In this program reverse (int num) is recursive, it calls itself until the condition is false. 2) Using Rev class object r, call the method reverse (x ) as r.reverse (x), then reverse (x) method starts the execution and calls itself as reverse (num) until num!=0.