How long will it take a ball to drop 1 meter?

So far I have: 9.8 m/s^2 (acceleration in free fall)/2 = 4.9 m/s (average speed over 1 second). So in one second the ball will have fallen 4.9 m. 1 m/4.9 m = (roughly) .

How long does it take for the ball to reach its maximum height?

1 Expert Answer So the ball reaches its maximum height after 3 seconds.

How long does it take a ball to fall 5m if it is dropped?

If the object fell from 5 m, the equation would look like this: (2*5 m)/(9.8 m/s^2) =1.02 s^2. Take the square root of the result to calculate the time it takes for the object to drop. For example, the square root of 1.02 s^2 equals 1.01 s.

How high does the ball hit the ground from?

A ball is dropped from a height of 60 meters above the ground. How long does it take to hit the ground? The ball will hit the ground in 3.5 sec.

How do you find the initial speed of a falling ball?

The initial speed is zero because the balls are dropped and not thrown. Therefore, we can solve for time: time2 = (2 × distance) / acceleration Substituting distance = 54 meters and acceleration = 9.8 meters/second 2, we get

What is the acceleration of the ball when it drops?

Assuming there is no significant air resistance, the ball will have traveled y=0.5g (t^2) meters during time t from its drop. g is the gravitational acceleration on earth (g~9.8m/s^2). For y=10m, and solving for t; Seniors using loophole to save for retirement.

How do you find the direction of velocity of a ball?

If it is a two-dimensional problem – that is, the ball is tossed at an angle from some height, then one needs to know both the horizontal speed when it hits the ground (hint: same as the initial horizontal speed) and the vertical speed as it hits the ground. Those two components will yield the velocity – that is the speed and direction.