How many 3 digit numbers have at least 2 digits that are the same?

there are 9∗9∗8 three digit numbers where all digits are different so 1000−9∗9∗8 which have at least two digits that are the same and then there are 9 numbers which have exactly three same digits so the number of three digit numbers where exactly two digits are the same is 1000−9∗9∗8−9=343.

How many numbers are possible with 2 digits?

The total number of two digit numbers is 90. From 1 to 99 there are 99 numbers, out of which there are 9 one-digit numbers, i.e., 1, 2, 3, 4, 5, 6, 7, 8 and 9. If one digit numbers are subtracted from 99 we get 90 two-digit numbers.

How many 3 digit numbers are formed where at least 2 of 3 digits are same?

Third digit can be filled with remaining 8 digits. Hence the number of three digit numbers formed such that at least 2 of its digits are same are 252.

How many three digit numbers are there with all the digits equal how many two digit numbers are there with the two digits are equal?

the second digit can be any number (10 possibilities) but cannot be equal to the first digit. Therefore, there are (10-1) 9 possibilities for the 2nd digit. The third digit can be any digit (10 possibilities) but cannot be equal to the first two digits. Therefore, there are (10-2) 8 possibilities for the 3rd digit.

How many combinations are there with 2 letters and 2 numbers?

325 possible combinations
There are 325 possible combinations with two letters.

How to calculate 3 digit numbers with exactly one digit as 5?

To calculate the 3 digit numbers with exactly one of its digit as 5, we need to use permutation and combination. Case 2) B=5, thus C be any digit but 5 while A can be any digit but 0 & 5. A cannot be 0 as it will violate the rule of being a 3 digit number.

How many possible first and second and third digits are there?

There are 9 possible first digits (I’m not counting 012 as a three digit number). There are 10 possible second digits. There are 10 possible third digits. Either the first and second (90), first and third (90), or second and third (90) must match.

What is the maximum possible 3-digit number in the range 999-100?

The answer is 900. Here’s how I found it. Take the largest possible 3-digit number in that range (999) and subtract the smallest possible 3-digit number in the same range (100) from it and then add one because you want to include the first counting number. The result is: Hope that helps!