How many digits does 50 factorial have?

How many digits does 50 factorial have?

12 zeroes
The number of 0’s is equal to the powers of 5 in the expansion of 50!. So, there are 12 zeroes in front of 50!

What is the last non zero digit of 50 factorial?

So the last non-zero digit is 4.

How do you find the last digit of a factorial?

= 5*4 * 3 * 2 * 1. = 120. Last digit of 120 is 0. A Naive Solution is to first compute fact = n!, then return the last digit of the result by doing fact \% 10….An Efficient Solution is based on the observation that all factorials after 5 have 0 as last digit.

  1. =
  2. =
  3. =
  4. =
  5. = 120.
  6. = 720.
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How do you find the last non zero digit of a factorial?

= 14 * 13 * 12 * 11 * 2 * 9 * 8 * 7 * 6 * 3 * 2 * 1 Now we can get last non-zero digit by multiplying last digits of above factors! In n! a number of 2’s are always more than a number of 5’s. To remove trailing 0’s, we remove 5’s and equal number of 2’s. Let a = floor(n/5), b = n \% 5.

How do you find the rightmost non zero digit of a factorial?

This post deals with calculating the last non-zero digit in a factorial….Calculate the right most non zero digit in 5!

  1. Here 5! = 5 x 4 x 3 x 2 x 1.
  2. In the product, there is one pair of 5 and 2. Ignoring this pair we get: 4 x 3 x 1.
  3. Units digit in 4x3x1 is 2 which is the right most non zero digit of 5!

How do you use a factorial calculator?

Factorial Calculator n! Factorial Calculator n! Factorial Calculator n! Instead of calculating a factorial one digit at a time, use this calculator to calculate the factorial n! of a number n. Enter an integer, up to 4 digits long. You will get the long integer answer and also the scientific notation for large factorials.

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What is the factorial of 5 factorials?

5 factorial is 5! = 5 x 4 x 3 x 2 x 1 = 120 0 factorial is a definition: 0! = 1. There is exactly 1 way to arrange 0 objects.

What is the exponent of 2 and 5 in 50?

First, the exponent of 2 in 50! is 25 + 12 + 6 + 3 + 1 = 47, and the exponent of 5 in 50! is 10 + 2 = 12 (by De Polignac’s formula ), so we’re looking for 50! 10 12 mod 10. Since 50! 10 12 is even (in fact, divisible by 2 35 ), it suffices to compute it mod 5: