How many natural numbers are there between 200 to 400 which are divisible by 4?

79 is the answer.

What are the numbers between 100 and 200 that are divisible by 4?

The first natural number which lies between 100 and 200 and is divisible by 4 is 104.

How many natural numbers are there between 200 and 500 which are divisible by 7 Teachoo?

Answer : The numbers between 200 and 500 that are divisible by 7 are 203, 210, 217, …, 497. ∴ There are 43 natural nos. between 200 and 500 which are divisible by 7.

How many natural numbers are between 200 and 500 which are divisible by 7?

43 numbers are divisible by 7 b/w 200-500.

How many natural numbers are there between 200 and?

What is the sum of all the numbers between 200 and 400 which are divisible by 7?

8729
Let the number of terms of the A.P. be n. Thus, the required sum is 8729.

How many natural numbers are there between 200 and 500 which are divisible by 8 also find their sum?

37
Now, a=208,d=8,L=496. Therefore, the no. of integers between 200 and 500 which are divisible by 8 are 37.

How many natural numbers are there between 200 and 500 which are divisible by?

∴ There are 43 natural nos. between 200 and 500 which are divisible by 7.

What is the sum of all natural numbers from 100 and 200?

Answer: The “sum” of all the multiples of 3 between the numbers “100 and 200” are 4950. Let the no.

What is the sum of all natural numbers between 200 and 400?

Find the sum of all natural numbers between 200 and 400 which are divisible by 7. Natural numbers between 200 and 400 which are divisible by 7 are 203, 210 ,…. 399. This is an AP with a = 203, d = 7 and l = 399. Suppose there are n terms in the AP. Then, Hence, the required sum is 8729.

How many numbers lie between 200 and 400 that are divisible by 7?

The numbers lying between 200 and 400 which are divisible by 7 are 203,210,217,…399 ∴ First term, a = 203

What is the sum of positive integers upto 400?

The number series 1, 2, 3, 4, . . . . , 399, 400. Therefore, 80200 is the sum of positive integers upto 400.

What is the sum of the last four terms in GP?

The sum of the last four terms is 112. If its first term is 11, then find the number of terms. Q13 If Q14 Let S be the sum, P the product and R the sum of reciprocals of n terms in a G.P. Prove that P2Rn = Sn Find the sum of all numbers between 200 and 400 which are divisible by 7.