How many numbers of five different digits each can be made from the digits 1 2 3 9 if the numbers must be odd?

Example1: How many different 2 letters words can be formed out of the letters A, B and C?

What is the number of 5-digit numbers formed with 0 1 2 3 4 without any repetition of digits?

∴ Total number of 5–digit numbers that can be formed using the digits 0, 1, 2, 3, 4 = 5! – 4! = 120 – 24 = 96.

How many numbers consisting of different digits can be made from the digits 1 2 3 4 If the last digit must be odd?

The answer is 36. Here’s a good way to find out how many ODD 5-digit umbers you can make from { 1. 2, 3, 4, 5 }.

How many 4 digit numbers formed using the digits 5 3 8 0 without repeating any digit would be odd and also multiples of 5?

18 4-digit numbers can be created using the digits 5, 3, 8, and 0 without repeating, and 4 of them are odd and a multiple of 5.

How many 5-digit numbers can be formed using (0-9)?

How many 5-digit numbers can be formed using (0-9)? You can have up to 10 combinations for each digit, times the number of… Numbers you want. The trick is to realize that a number can not start with a zero! Now, there are 105 ways in which the digits 0-9 can be chosen for the five places of a five digit number.

How many combinations can you have for a 5 digit number?

You can have up to 10 combinations for each digit, times the number of… Numbers you want. The trick is to realize that a number can not start with a zero! Now, there are 105 ways in which the digits 0-9 can be chosen for the five places of a five digit number.

What is the total number of choices for the first digit?

For the third number, there are 4 choices, for the fourth number there are 3 choices, and for the fifth number there are 2 choices. Thus, the total number of choices is (5) (5) (4) (3) (2) = 600. Alternatively, use the same logic and realize there are 5 choices for the first digit.

What is the first and second digit of a 5 digit number?

For the first digit, there are only five options (5, 6, 7, 8, and 9) because a five-digit number must start with a non-zero integer. For the second digit, there are 5 choices again, because now zero can be used but one of the other numbers has already been used, and numbers cannot be repeated.