Table of Contents
- 1 How many possible combinations of input variables exist in a 4 variable expression?
- 2 How many possible combinations will be in the truth table of a 4 input NAND gate?
- 3 How many inputs can an OR gate have?
- 4 How many inputs can a logic gate have?
- 5 Why the truth table of an AND gate has four possible combinations?
- 6 How many input combinations can a 4 input gate have?
- 7 How many possible inputs are there among 8 possible inputs?
How many possible combinations of input variables exist in a 4 variable expression?
Each of four inputs may be a 1 or 0, making 2^4 = 16 total input combinations.
Can logic gates have 4 inputs?
Because the Boolean expression for the logic AND function is defined as (.), which is a binary operation, AND gates can be cascaded together to form any number of individual inputs. However, commercial available AND gate IC’s are only available in standard 2, 3, or 4-input packages.
How many possible combinations will be in the truth table of a 4 input NAND gate?
Therefore, a 3-input logic circuit would have 8 possible input combinations or 23 and a 4-input logic circuit would have 16 or 24, and so on as the number of inputs increases. Then a logic circuit with “n” number of inputs would have 2n possible input combinations of both “OFF” and “ON”.
How many outputs does 4 inputs have?
So, a 4-input AND gate has 16 possible combinations, 5 inputs would be 32 outputs, and so on. Can you think of a situation in real life where three requirements must be met before an outcome becomes true?
How many inputs can an OR gate have?
Like the AND gate, the OR function can have any number of individual inputs. However, commercial available OR gates are available in 2, 3, or 4 inputs types. Additional inputs will require gates to be cascaded together for example.
How many combinations are there for a four input gate?
16 possible combinations
So, a 4-input AND gate has 16 possible combinations, 5 inputs would be 32 outputs, and so on.
How many inputs can a logic gate have?
two inputs
In a circuit, logic gates will make decisions based on a combination of digital signals coming from its inputs. Most logic gates have two inputs and one output. Logic gates are based on Boolean algebra.
How many inputs of a four input AND gate must be high in order for the output of the logic gate to go high?
How many inputs of a four-input AND gate must be HIGH in order for the output of the logic gate to go HIGH?…Discussion :: Logic Gates – General Questions (Q. No. 25)
[A]. | any one of the inputs |
---|---|
[C]. | any three of the inputs |
[D]. | all four inputs |
Why the truth table of an AND gate has four possible combinations?
Because there are two possible input values for two different input channels, there are four possible input combinations for an AND gate. These input combinations and their respective outputs are shown below. We will use color to code the binary values with red representing 0 and blue representing 1.
How many rows are there in a logic gate?
I still have the design files for those, if anybody is interested in seeing how to do that. There are 2^ (No. of inputs) rows in a logic gate. So for 2 inputs there are 2^2 i.e. 4 rows, for 3 inputs there are 2^3 i.e. 8 rows, and for a 4 input logic gate there are 2^4 i.e. 16 rows.
How many input combinations can a 4 input gate have?
For instance, a 4 input OR gate goes TRUE if any single input is true. Therefore you could conceivably get away with two input combinations- 0000 and “Everything else”. Likewise, a 4 input AND could have two entries- 1111 and “Everything else”.
How many possible combinations of functions can be used with two inputs?
Assuming bivalent logic (1/true or 0/false), two inputs can be in 2 squared = 4 combinations. Each function output can be either 0 or 1 for each of those 4 combos, so there are 2 to the 4th = 16 possible functions.
How many possible inputs are there among 8 possible inputs?
For two inputs, output is high when both inputs are high (1×1=1) Similarly, here too output will be high for input 111 (1×1×1). So possibility among 8 possible input is 1/8 . Is it possible to make a 3 input NAND or NOR gate with 2 input NAND or NOR gates?