Table of Contents
- 1 How many quadrilaterals can be formed from 10 points no three of which are collinear?
- 2 How many quadrilaterals can be formed joining the vertices of polygon of 12 sides?
- 3 How many quadrilaterals can be formed by joining?
- 4 How many quadrilaterals can be formed by joining vertices of Octagon?
- 5 How many quadrilaterials with two common sides have 84 common sides?
- 6 How many ways can you choose the Common side of a polygon?
How many quadrilaterals can be formed from 10 points no three of which are collinear?
10 points lie in a plane, of which 4 points are collinear. Barring these 4 points, no 3 of the 10 points are collinear. How many distinct quadrilaterals can be drawn? Adding them up I got 185 ways, but the answer is 209, which I don’t understand how.
How many quadrilaterals can be formed joining the vertices of polygon of 12 sides?
Now, when joining the vertices of a polygon, 12 sides means total 12 points among which any 4 will produce a possible quadrilateral. So, the answer is the possible ways we can choose any 4 points from the 12 points of the polygon we’ve got. So, it can be expressed as, C(12,4) = 12! / [4!
How many quadrilaterals can be formed by joining the vertices of a 12?
Step-by-step explanation: Now, when joining the vertices of a polygon, 12 sides means total 12 points among which any 4 will produce a possible quadrilateral. So, the answer is the possible ways we can choose any 4 points from the 12 points of the polygon we’ve got. So, it can be expressed as, C(12,4) = 12! / [4!
How many quadrilateral parts can be formed by joining the vertices of a site in the form of a hexagon?
Hexagon
| Regular hexagon | |
|---|---|
| A regular hexagon | |
| Type | Regular polygon |
| Edges and vertices | 6 |
| Schläfli symbol | {6}, t{3} |
How many quadrilaterals can be formed by joining?
How many quadrilaterals can be formed by joining vertices of Octagon?
Permutation and Combination #49
| 49. How many quadrilaterals can be formed by joining the vertices of an octagon? | |
|---|---|
| A. 70 | B. 65 |
| C. 74 | D. 60 |
How many ways to choose sides of a quadrilateral?
By quadrilateral we mean convex quadrilateral. (1) As in your solution, there are 12 ways to choose the side in common with the 12 -gon. The “opposite” side’s vertices are chosen from the 8 remaining candidate vertices. There are ( 8 2) ways to choose 2 vertices.
How many distinct quadrilaterials can be formed from 12 consecutive vertices?
Multiply by 12, because we said there are 12 different ways to chose a pair of consecutive vertices and you’ll get 252 distinct quadrilaterials. For the second problem you should look in two cases. The one is when the two common sides are consecutive (we use 3 consecutive vertices). Again there are 12 such triples.
How many quadrilaterials with two common sides have 84 common sides?
We are dividing by two, because the same quadrilaterial can be reached starting from A 1, A 2 and A 5, A 6, so every quadrilaterial is calcualted twice. Add those two numbers and you’ll end up with: 84 + 42 = 126 quadrilaterials with two common sides.
How many ways can you choose the Common side of a polygon?
A start: (i) The side common with a side of the polygon can be chosen in 10 ways. Take one of these ways. In how many ways can we choose the remaining 2 vertices?