How many roots does x2 2x +1 0 have?

How many roots does x2 2x +1 0 have?

Alternatively, you could say that x2−2x+1=0 has exactly two roots, counting multiplicity.

What is the discriminant of x2 2x 1 0?

Explanation: D = 4 – 4 = 0. This means there is a double root at x = – 1 .

Can you factor x 2 2x 2?

This is not factorable normally. We can see this since x2−2x+1 is a perfect square, so it touches the x-axis at a single root. Adding 1 to this produces x2−2x+2 , and raises the graph of y=x2−2x+1 one upwards, meaning it no longer touches the x-axis, so it has no real roots.

What is the root of polynomial equation 2x 3 0?

So, the correct answer of this question is option (3) -3/2.

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How do you find the discriminant?

The discriminant is the part of the quadratic formula underneath the square root symbol: b²-4ac. The discriminant tells us whether there are two solutions, one solution, or no solutions.

What is the value of discriminant of X² 2x?

The value of discriminant is -16.

How do you solve x2 + 2x + 1?

To solve the equation, factor x 2 + 2 x + 1 using formula x 2 + ( a + b) x + a b = ( x + a) ( x + b). To find a and b, set up a system to be solved. Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive.

How do you solve Ax^2}+bx+c=0 using the quadratic formula?

All equations of the form ax^ {2}+bx+c=0 can be solved using the quadratic formula: \\frac {-b±\\sqrt {b^ {2}-4ac}} {2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction. . The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.

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How to find the extraneous root of x^2+x+1=0?

In effect, you have taken the equation x^2+x+1=0, divided by x to get x+1+\\frac1x=0 and then multiplied by x-1 to get x^2-\\frac1x=0. The extraneous root 1 is the solution of x-1=0,