How many three digit numbers have at least one 5 as a digit?

That makes 648 combinations with no 5. All the rest have either 1, 2 or 3 fives in them. 900 – 648 = 252. That’s your answer.

What is a 5 digit natural number?

Numbers up to 5-digits are the integers on the number line that start from 10,000 and extend up to 99,999.

How many three digit numbers are there which have 5 in the unit place?

Hence there are 180 three digit numbers divisible by 5. Hence option [a] is correct.

How many possible 5-digit numbers are there?

The smallest 5 5 -digit number is 10000, 10000, while the largest 5 5 -digit number is 99999. 99999. These 90000 90000 possible 5 5 -digit numbers can have any number from 0 0 to 9 9 in any of the places, except for the placement of zero such that there is no non-zero number to its left.

How many 3 digit numbers are there without a 3?

1000 does not contain a 3. So, count the number of 3 digit numbers without a three. There are 9 choices for the first entry, 9 for the second, and 9 for the third. So, there are 729 numbers without a 3, and 1000-729 = 271 with a 3.

What is the total number of combinations possible with 5 numbers?

Overall, every one of the 5 places of a 5-digit number can be filled up in ten ways, because it can have 0, 1, 2, 3, 4, 5, 6, 7, 8, or 9. So each of the five places can be similarly filled up in ten ways. Therefore, the total number of combinations possible are 10 × 10 × 10 × 10 × 10 = 1,00,000.

How do you find the place value of a 5 digit number?

The place value of the five digits that make up the 5-digit number would be obtained by progressively multiplying the respective figure by 1, 10, 100, 1,000, and 10,000 starting from the rightmost digit and moving to the left. As shown above, is a 5-digit number, every progressive place value is the earlier place value multiplied by 10.