How many ways 4 boys and 4 girls can be seated in a row such that number two boys are together?

ways . =>37440 ways.

How many ways can 4 boys and 4 girls sit on a circular table such that the 4 girls always sit together?

There are 4 boys and 4 girls; they can be permuted among themselves in 8! = 40320 ways.

How many possible orders can 2 boys and girls sit on a college bench?

options (3! for order of boys and 2! for girls), so we do indeed have 3×3! 2! =36 ways.

What is the number of ways that 4 boys and 3 girls can be?

Thus, the required number of ways will be 144 ways.

How many ways can we arrange 4 boys around a circle table?

There are 4! ways to assign the 4 boys to the 4 positions, but allowing for rotations, this counts each “essentially different” arrangement 4 times. So the total number of arrangements is 4! / 4 = 3! = 6.

How many ways can 6 people sit around a round table?

Example 1 In how many ways can 6 people be seated at a round table? Solution As discussed in the lesson, the number of ways will be (6 – 1)!, or 120.

How many ways can 4 boys and 4 girls be arranged?

So there are 4 boys + 1 ‘person’ = 5 objects, which can be arranged in 5! ways. But the group of 4 girls can arrange themselves in 4! ways, so the total number of ways where the girls sit together is 5! x 4! Unrestricted, 4 boys and 4 girls can be arranged in 8! ways.

How many ways can a group of 4 girls sit together?

Treat the group of 4 girls as 1 ‘person’. That is, they are sitting together. So there are 4 boys + 1 ‘person’ = 5 objects, which can be arranged in 5! ways. But the group of 4 girls can arrange themselves in 4! ways, so the total number of ways where the girls sit together is 5! x 4! Unrestricted, 4 boys and 4 girls can be arranged in 8! ways.

How many arrangements of boys in a row?

First, let us consider the order of the boys, ignoring the placement of the girls. Given 7 boys, there are 7! = 5040 arrangements of boys in a row. Note that there are 8 spaces in which to place girls. We can’t have more than one girl per space, or else the condition that “no two girls come together” is not satisfied.

How many ways can 4 boys be seated in 4?

We have 4 boys and 3 girls arranged in a row such that no two girls are adjacent. I would first start off with arranging/seating the boys . 4 boys can be seated in 4! ways. Thus 4 boys can be seated in 4! = 4 ∗ 3 ∗ 2 ∗ 1 = 24 ways.