How many ways can you place 9 different books on a shelf if there is space enough for only 5 books *?

n how many ways can you place 9 different books on a shelf if there is space enough only 5 books? ution: Pn,r=frac n! m-r! Answer: There are 15120 ways that 9 different books can bi P9,5=frac 919-5!

How many ways can 9 different books be arranged on a shelf?

We know that the two books that are kept together can be arranged in two ways. So, we will get the total number of ways we can arrange the $9$ books. Hence, we can arrange the $9$ on a shelf in $40320\times 2=80640$ ways.

What is 5th number statement?

R D Sharma – Mathematics 9 Step-by-step explanation: We are given to find the fifth number, where the first and second numbers are 1 and 2 respectively. We will consider the following two cases to find the fifth number which includes addition and multiplication. Thus, the 5th number can be 5 or 16.

How many ways can you order 9 things?

Unlock Overall, it looks like 9x8x7x6x5x4x3x2x1, or 362,880 ways of arranging the people. Have fun! Some calculators have a factorial button on them, but if you just have a scientific calculator, just punch in the numbers.

How many ways can you arrange 7 different books on a shelf?

Having filled the first place with any one of the 7 books we are left with 6 books. The second place now can be filled up by any on of 6 books and so on. We can thus fill up all the 7 places in 7 (6) (5) (4) (3) (2) (1) = 7! = 5040 ways. Hence we can arrange 7 different books on a shelf in 5040 ways.

How many ways can you arrange 9 books in a row?

There are 8 choices for the first book, 7 for the next, 6 for the next, etc. ways to arrange the 8 books. Then you can place the reserved book on either side of its companion. So for each of the possible 40320 ways to arrange the other 8 books, there are 2 possible acceptable arrangements of 9 books.

How many ways can you fit 10 books in 6 places?

ANS: Therefore the number of ways 10 books can be fit in 6 places is 10*9*8*7*6*5 = 1,51,200. None.It’s very easy to see the combinations problem that the math teacher wanted to set, but they have failed to do so.

How many ways can the three books be arranged among themselves?

The three books can be arranged among themselves in 3 (2) (1) = 6 ways. Further, these three books S with the other 4 books form 5 books. These 5 books can be as in a) above be arranged in 5 (4) (3) (2) (1) =5! = 120 ways.