Table of Contents

## What are all the 4 number combinations?

There are 10,000 possible combinations that the digits 0-9 can be arranged into to form a four-digit code. Berry analyzed those to find which are the least and most predictable.

## How many 2 number combinations are there in the numbers 1 to 9?

I also know that there are 100 combinations of two digits from 0-9, and 10 ombinations of one digit from 0-9. How do I know this? 10 10 = 100 two digit combinations. 10 10 10 = 1000 three digit combinations.

**How many 4 digit numbers can be formed with the digits 5 9 1 and 31 li?**

Answer: Infinite numbers will form.

**How many 4 digit numbers are there that have no single digit repeated in it?**

So there are 4 x 3 x 2 x 1 = 24 possible ways of arranging 4 items. Therefore I divide 5040 / 24 = 210. So there are 210 different combinations of four digits chosen from 0-9 where the digits don’t repeat.

### How many 3 digit combinations can 4 numbers make?

For the third digit there are only 2 choices and for the last digit, one choice. Thus if you are not allowed to repeat a digit the number of possible 4 digit numbers you can construct from 1,2,3,4 is 4 3 2 1 = 24.

### How many 4 digit numbers can be formed by combining 1-9?

If you are asking “how many 4 digit numbers can be formed by combining the digits 1 to 9?,” the answer is 9^4 if by “combining” you mean concatenating (listing one after another). The answer is 9^4 or 6,561. Careful counting of the combinations will get you the answer.

**How many possible combinations of 5 and 4 are there?**

There are 5 ⋅ 4 possibilities that satisfy this. The third can be any of the 5, so there are 5 ⋅ 4 ⋅ 5 = 100 possibilities for the first case. In the second case, the first two digits are the same. There are 5 ⋅ 1 = 5 ways this can occur. In this case, the third digit must be different, giving you only 4 options to chose from.

**How many possible combinations of numbers are there between 0-9?**

Assume that the digits go from 0-9. If the possibilities are 0 to 9, there are 10 possible first nnumber combinations. If a second one was added, every 10 of those possibilities can ba matched with one of the first ones, so 10 (first set) ×10 (second set) =100 possibilities.

#### Can 4 numbers have more than 9 possible values?

Yes assuming you mean 4 digits each with a possible selection of 1 – 9, then each digit has 9 possible values. The Rock reveals the key to success for normal people. The big companies don’t want you to know his secrets.