What force must be added to a 60 N force in the direction 090 in order to have a resultant of 100 N in the direction 045?

solution

tan θ =	Fy
θ =	45°

What are the components of 60 N force acting horizontal in two directions on either side at an angle 30 each?

The two resolved components are always of the form: Value sine(angle theta) , Value cos(angle theta) . The value in this case is 60N, If a componet is 30 N (ie half) this means cos theta =0.5 and so theta is 60 degrees.

What is the resultant force when two forces act at 120 degrees?

When both are making an angle A with each other. If both are in same direction, then see result in case 1 of the image. If both are in opposite directions, then see in case 2 of the image. if they are in opposite direction, I.e. Anti parallel, then resultant force is F=F1-F2. Two forces act at an angle of 120 degrees.

How do you find the direction of resultant force?

Resultant Force = √ ( (5 x cos (20) + 8 x cos (25)) 2 + (5 x sin (20) + 8 x sin (25)) 2) = 13 N. Direction Angle Of Resultant Force = tan -1 ( (5 x sin (20) + 8 x sin (25))/ (5 x cos (20) + 8 x cos (25))) = 23 °. The direction angle of resultant force is calculated from the resultant of two forces acting at an angle.

What is the resultant force of tan -1?

Resultant Force = √ ((F 1 × cos (A) + F 2 × cos (B)) 2 + (F 1 × sin (A) + F 2 × sin (B)) 2) R = tan -1 (F 1 ×sin (A) + F 2 × sin (B))) / ((F 1 × cos (A)+ F 2 × cos (B)) Where, F 1 = First Force F 2 = Second Force A = Direction Angle of First force B = Direction Angle of Second Force R = Direction Angle of Resultant Force

What is the resultant force from a rod with magnitude 150?

So the resultant force has magnitude 150 N and acts at a distance of 240 mm from the left end of the rod. thus, the resultant force of 150N acts on the rod at a point 240mm away from the end of the rod where force of 50N is acting.