What is 2 and a half as an improper fraction?

212 as an improper fraction is 52 .

What is a solution set in math?

In mathematics, a solution set is the set of values that satisfy a given set of equations or inequalities. For example, for a set of polynomials over a ring , the solution set is the subset of on which the polynomials all vanish (evaluate to 0), formally.

How do you know if an equation has 2 solution?

Here’s how the discriminant works. Given a quadratic equation ax2 + bx + c = 0, plug the coefficients into the expression b2 – 4ac to see what results: If you get a positive number, the quadratic will have two unique solutions. If you get 0, the quadratic will have exactly one solution, a double root.

How do you make a 1 in 2 solution?

To make a solution that is 1 in 2 (mL or otherwise) you will add 1 portion (e.g., mL) to 1 mL of water. The total volume will be 2 mL and 1 mL will be whatever you are diluting for 1 in 2. For 1 in 5, same idea, and use 1 mL of what you are diluting to 4 mL of water. The total volume will be 5 ml so you will have 1 mL in a total volume of 5 mL.

What is the ratio of 1 2 in chemistry?

The ratio 1:2 is a 50\% solution, so let’s say 1:2 is in respect to substances A : B. This means that if you have solvent e.g. water as B and Substance as A: By taking one volume of the original solution and diluting it to two volumes.

What is a 1 2 dilution solution used for?

a 1:2 dilution is usually used for Volume #1 out of Volume #2 . Vol1/vol2 . In this case you want a certain substance Volume. And double the amount of solvent to dilute it . That will give you a solution of 3 x times the substance to dilute volume. Easy : 50ml of x dilute with 100ml of solvent.

How to solve ax = b with a particular solution?

A particular solution One way to find a particular solution to the equation Ax = b is to set all free variables to zero, then solve for the pivot variables. For our example matrix A, we let x2 = x4 = 0 to get the system of equa­ tions: x1 + 2×3 = 1 2×3 = 3 1. which has the solution x3 = 3/2, x1 = −2.