What is amount of water produced by the combustion of 8g methane?

According to the above equation, one mole of CH4 (8 g) on combustion gives one mole of carbon dioxide and 2 moles of water and 2 moles of water = 2 x [2 + 8] = 20 g of water.

How many moles of water would be produced when 8 g of methane CH 4 are burnt?

1 mol
The number of moles of water produced are. 16gm CH4 produced 2 mol water therefore 8gm will produce 1 mol of water.

What amount of CO2 is obtained by the combustion of 8 g of methane?

Now let’s convert the grams of methane and oxygen to moles and see which one is the limiting reagent. So11 grams of carbon dioxide are produced.

How much water is produced by the combustion of 16G of methane?

Amount of water produced by the combustion of 16g of methane is: According to the above equation, one mole of CH4 (16 g) on combustion gives one mole of carbon dioxide and 2 moles of water and 2 moles of water = 2 x [2 + 16] = 36 g of water.

How many grams of ethane are produced from 8 grams of CH4?

See what the community says and unlock a badge. Therefore 8 gms ethane produced = 14.4 gms According to the above equation, one mole of CH4 (8 g) on combustion gives one mole of carbon dioxide and 2 moles of water and 2 moles of water = 2 x [2 + 8] = 20 g of water.

How do you calculate the mass of 2 moles of water?

Two moles of water is 36 g. 30 g of methane = 30 g / 16 g per mole gives 1.875 moles. The amount of water produced is 2 moles times 1.875 gives 3.75 moles. To calculate for the mass of 3.75 moles of water we multiply 3.75 moles by 18 grams per mole and get a product of 67.5 g.

How many moles of methane are in 16G of it?

O. Given weight of methane = 16g. Molecular weight of methane = 16g. No. of moles of methane in 16g of it = mol. wt.given wt. ​. = 1616. ​. = 1 mole. From the reaction,