What is an efficient algorithm to find divisors of any number?

What is an efficient algorithm to find divisors of any number?

Currently the most efficient algorithm is Shor’s algorithm , but it requires a quantum computer….This is the most efficient algorithm I know.

  • Start by inputting a number. n.
  • Let an int variable. limit. be sqrt(n)
  • Run a loop from. i=1. to. i=limit. 3.1 if. n. is divisible by. i.
  • End.

How do you find divisors in Java?

To get the divisor of a number N, we should divide N by all numbers in between 1 and N including 1 and N. We will use modulus operator which gives reminder. If reminder is zero, we can say given number is divisible by another number. For ex: 10\%2= 0 (10 is divisible by 2 without a reminder)

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What are the divisors of 10?

Divisors of numbers

Number Prime factorization Divisors
8 23 1, 2, 4, 8
9 32 1, 3, 9
10 2 * 5 1, 2, 5, 10
11 11 1, 11

How do you find the number of divisors of an integer?

Plug in the value of each exponent into the formula for determining the number of divisors, or factors, in a number. Once you’ve put the values into the formula, add the values in parentheses, then multiply all of the values in the parentheses. The product will equal the number of divisors in the integer.

What is the smallest integer with 6 divisors?

If you mean six different divisors (and assuming all divisors must be positive integers), the smallest possible integer would be 1 x 2 x 3 x 4 x 5 x 6 = 720. Thanks! Is there an equation to find the number of divisors for an integer number? Yes. It’s given and explained in Step 2 above. Thanks!

How do you find the divisors of a prime number?

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All you do is prime factorization first, then loop through all the exponents possible. Using this method you can get the divisors of even very large numbers relatively quickly, but it still wouldn’t work that well for products of very large primes since the prime factorization would still take a while.

What is the difference between finding factors and creating divisors?

Note that step 2 — creating the divisors from the factors, is trivial in time compared to finding the factors, except for some pathological cases such as primorials where the factoring is trivial but the number of divisors grows very rapidly. Optimizing for efficiently returning hundreds of thousands to billions of divisors is a different issue.