What is angle of projection of a body with the horizontal when its horizontal range is times the maximum height reached?

Motion in A Plane. Prove that the maximum horizontal range is 4 times the maximum height attained by a projectile. The horizontal range is maximum when the angle of projection is 45°.

At what angle with the horizontal a projectile be projected so that the horizontal range and maximum height become same?

45∘
The angle of projection at which the horizontal range and maximum height of projectile are equal is. 45∘

What is the angle of projection at which horizontal range?

Complete step by step answer: If the angle of projection is \[{75.96^ \circ }\], the maximum height is equal to the horizontal range. In this condition, \[u\] represents the beginning speed extent and \[\theta \] is the angle of projection to the shot point.

What is the angle of projection when the horizontal duration of the projected object is maximized?

45°
Maximum Range: It is the longest distance covered by the object during projectile motion. When the angle of projection is 45°, the maximum range is obtained.

How do you find angle of projection?

The maximum height achieved by a projectile ignoring the air resistance is given by HM=U2Sin2 θ 2g… (1) where U is the initial velocity, θ is the angle of projection and g is the acceleration due to gravity. The horizontal distance covered by the projectile i.e. range is given by, R=U2Sin2 θ g… (2).

At what angle theta to the horizontal should an object be projected from the ground so that the maximum height reached is equal to horizontal range?

45° angle
where R = Horizontal Range, V0 = Initial velocity, θ = The angle at which object is projected or thrown. Hence, horizontal range will be maximum when object is projected at 45° angle with the horizontal.

How do you find the projected angle?

The horizontal distance covered by the projectile i.e. range is given by, R=U2Sin2 θ g… (2). We want to calculate the angle of projection for the condition i.e. Hence the angle of projection should be 36.86 degrees.

What is angle of projection?

(i) Angle of projection – It is the angle with the surface with which the projectile is projected. The maximum range angle of the projectile should be 450.

When a particle is projected at an angle theta with horizontal with an initial speed u then?

When the particle makes an angle ϕ with the horizontal, its speed changes to v. A particle is thrown with a speed u at an angle θ with the horizontal. When the particle makes an angle ϕ with the horizontal, its speed changes to v.

What is the angle of projection for which horizontal range and height?

Expert Answer: Let θ be the angle of projection for which horizontal range and maximum height of a projectile are equal.Now, H= u 2 sin 2 θ / 2g R = u 2 sin2θ / g

What is the range of a projectile?

A projectile is fired in such a way that it’s horizontal range is equal to three times it’s maximum height. What is the angle of projection? | Socratic

What is the angle of projection of a body?

A body is projected at such an angle that the horizontal range is three times the greatest height. The angle of projection is The Fish Tale Across the Wall Tenths and HundredthsParts and Whole Can you see the Pattern?

What is the horizontal component of the velocity at maximum height?

The horizontal component of the velocity does not change. At the maximum height the vertical velocity is equal to 0. As this is equal to the range: If the angle of projection is 75.96 degrees the maximum height is equal to the horizontal range.