What is the 15th term of arithmetic progression?

As we know the nth term of an A.P. is $ {a_n} = a + (n – 1)d $ where $a$ is the first term, $d$ is the common constant difference. According to the question we have to find the value of the 15th term, so $ n = 15 $ So the 15th term of the A.P. will be $ {a_{15}} $

How do you get a15?

If you know the first term of an arithmetic sequence, a1, and the common difference, d, then you can find the nth term, an , using the following rule. Step 3 Use the formula with n = 15 to find the 15th term, a15. an = a1 + (n − 1)d Write the rule. a15 = a1 + (15 − 1)d Substitute n = 15.

What is the sum of the first 15 terms of the sequence?

Thus, the sum of the first fifteen terms in the arithmetic sequence is 975 .

What is the geometric mean of 4 and 9?

6
The geometric mean between 4 and 9 is 6.

How do you find the first term of an arithmetic progression?

The formula for finding n t h term of an arithmetic progression is a n = a 1 + ( n − 1) d , where a 1 is the first term and d is the common difference. The formulas for the sum of first n numbers are S n = n 2 ( 2 a 1 + ( n − 1) d) and S n = n 2 ( a 1 + a n) .

How do you find the first term if you have two terms?

If I had two terms I could use the n − th term formula to calculate the first term. For example: The second term of an arithmetic sequence is 4. The fifth is 10. Find the first term. In this task we have 2 terms given: a2 = 4 and a5 = 10. We can use the n −th term formula to build a system of equations: {a1 + d = 4 a1 + 4d = 10.

How do you find the 26th term of an arithmetic sequence?

To find any term of an arithmetic sequence: Where is the first term, is the number of the term to find, and is the common difference in the sequence. Find the 26th term of the following arithmetic sequence. Start by finding the common difference in terms by subtracting the first term from the second.

What is the formula to find the nth term of an AP?

Formula Lists General Form of AP a, a + d, a + 2d, a + 3d, . . . The nth term of AP an = a + (n – 1) × d Sum of n terms in AP S = n/2 [2a + (n − 1) × d] Sum of all terms in a finite AP with the n/2 (a + l)