Table of Contents
- 1 What is the equation of a circle with Centre at 2/3 and a radius of 4?
- 2 What is the equation of a circle with center (- 2 3?
- 3 What is the equation of a circle with center 2?
- 4 What is the equation of a circle with Centre 2 3 and radius 3?
- 5 How do you find the center of a circle with Y=X-4?
- 6 What is the equation of circle?
What is the equation of a circle with Centre at 2/3 and a radius of 4?
The equation of the circle with center (2, -3) and a radius of 4 is x2 + y2 – 4x + 6y = 3.
How do you find the equation of a circle given the center and a point?
Starts here3:26Write the equation of a circle given the center and a point it passes
throughYouTubeStart of suggested clipEnd of suggested clip60 second suggested clipAnd that equation is X minus H squared plus y minus K squared equals R squared.MoreAnd that equation is X minus H squared plus y minus K squared equals R squared.
What is the equation of a circle with center (- 2 3?
⇒(x+2)2+(y+3)2=9 is the circle’s equation.
How do you find the equation of a circle given the center and a tangent line?
Starts here3:33Find the standard equation of a circle given a center and a tangent lineYouTubeStart of suggested clipEnd of suggested clip53 second suggested clipX minus H quantity squared. Plus y minus K quantity squared equals R squared. The equation is X plusMoreX minus H quantity squared. Plus y minus K quantity squared equals R squared. The equation is X plus 3 quantity squared plus y minus 2 quantity squared equals 13.
What is the equation of a circle with center 2?
The equation of a circle with center (h,k) and radius r units is (x−h)2+(y−k)2=r2 .
What is an equation of a circle with center − 2 − 1 and radius 3?
The equation of the circle whose center is (2,1) and radius is 3 is (x – 2)2 + (y – 1)2 = 9.
What is the equation of a circle with Centre 2 3 and radius 3?
Explanation: The eqn. of a circle with centre (h,k) and radius r is given by, (x−h)2+(y−k)2=r2 .
What is the equation of a circle with center?
How do you find the center of a circle with Y=X-4?
It is y+3=x-4 (the slope of this line is 1). The center of the circle should be on the intersection of lines y+3=x-4 (or y=x-7) and x-y=1 (or y= x-1). Lines y=x-7 and y = x-1 are parallel, their intersection does not exist.
What is the radius of the circle perpendicular to 3x-4y+1?
Now you know the radius of the circle, it is 1. The line perpendicular to 3x-4y+1=0 and which passes through (2, 3) is 4x+3y-17=0. The intersection of the two lines is the tangent point of the line and circle at (13/5, 11/5).
What is the equation of circle?
Hence, the equation of circle is x 2+y 2−4x−2y+4=0. Was this answer helpful? A line is at a constant distance c from the origin and meets the coordinates axes in A and B.
How do you find the distance between a circle and a line?
When you say the circle touches that line, it means the line is tangent to it, thus, the distance between the center C and the line [math]5x + 12y – 19 = 0 [/math] is exactly the radius. Something like that. Where a, b, and c are the coefficients of the line (ax + by + c = 0), and x and y are the coordinates of the point.