What is the equation of a circle with its center at the origin 0 0?

The standard form equation of a circle is (x – h)2 + (y – k)2 = r2, centered at (h, k) with radius r. This circle is centered at the origin (0, 0), therefore (h, k) = (0, 0) and the equation becomes x2 + y2 = r2.

What is the equation of the circle passing through the origin?

We will learn how to form the equation of a circle passes through the origin. The equation of a circle with centre at (h, k) and radius equal to a, is (x – h)2 + (y – k)2 = a2.

What is the equation of the circle with center at the origin and radius 10?

Explanation: The equation of a circle with center (h,k) and radius r is given by (x−h)2+(y−k)2=r2 . For a circle centered at the origin, this becomes the more familiar equation x2+y2=r2 .

What is the equation of a circle with a center at the origin and that passes through the point 3/4 )?

Explanation: The general equation is (x−a)2+(y−b)2=r2 where (a,b) is the centre and the radius is r . The circle passes through (3,4), if we make a right angle triangle with this point and the origin.

What is the equation of a circle which passes through 3/6 and touches the axes?

The equation of circle passing through (3, 6) touching both the axes is.

What is the equation of a circle if the center is at the origin and the radius is 6?

So, if the center is (0,0) and the radius is 6, an equation of the circle is: (x-0)2 + (y-0)2 = 62.

How to find the equation of the circle which passes through origin?

Find the equation of the circle which passes through origin, has its centre on the line x + y = 4 and cuts orthogonally the circle x^2 + y^2 Find the equation of the circle which passes through origin, has its centre on the line x + y = 4 and cuts orthogonally the circle x2 + y2 − 4x + 2y + 4 = 0.

What is the equation for a circle that cuts a line?

A circle passes through origin and has its centre on the line y = x. If the circle cuts the circle x2 + y2 – 4x – 6y +10 = 0 orthogonally, then its equation is (A) x2 + y2 + 2x + 2y = 0 (B) x2 + y2 + 2x – 2y = 0

How do you find the equation of a circle with center?

The equation of circle with (h,k) center and r radius is given by: (x-h) 2 + (y-k) 2 = r 2. Thus, if we know the coordinates of the center of the circle and its radius as well, we can easily find its equation. Example: Say point (1,2) is the center of the circle and radius is equal to 4

Which is the standard form for the equation of a circle?

which is called the standard form for the equation of a circle. Equation of a Circle in General Form The general equation of any type of circle is represented by: x2 + y2 + 2gx + 2fy + c = 0, for all values of g, f and c.