What is the initial velocity of the ball at maximum height?

– Physics Q&A A ball is thrown vertically upwards with a velocity of 49 m/s. Calculate (1) The maximum height to which it rises. (2) The total time it takes to return to the surface of the earth. Initial velocity of the ball (u) = 49m/s. The velocity of the ball at maximum height (v) = 0.

What is the formula for distance from the ground in physics?

Distance. Horizontal distance traveled can be expressed as x = Vx * t, where t is the time. Vertical distance from the ground is described by the formula y = h + Vy * t – g * t² / 2, where g is the gravity acceleration. Velocity. Horizontal velocity is equal to Vx. Vertical velocity can be expressed as Vy – g * t. Acceleration

What happens to a projectile when it reaches its maximum height?

When the projectile reaches the maximum height, it stops moving up and starts falling. It means that its vertical velocity component changes from positive to negative – in other words, it is equal to 0 for a brief moment at time t (Vy=0). If Vy – g * t (Vy=0) = 0, then we can reformulate this equation to t (Vy=0) = Vy / g.

How do you find the time needed to reach maximum height?

From that equation we can find the time th needed to reach the maximum height hmax: th = V₀ * sin(α) / g. The formula describing vertical distance is: y = Vy * t – g * t² / 2. So, given y = hmax and t = th, we can join those two equations together: hmax = Vy * th – g * th² / 2. hmax = V₀² * sin(α)² / g – g * (V₀ * sin(α) / g)² / 2

What is the acceleration when a ball is thrown vertically upward?

When a ball is thrown vertically upward, it’s acceleration is -g(-9.8m/s) because it’s motion is in opposite direction to the gravitational attraction on the body, it’s velocity, v, at it’s highest point is zero while it’s initial velocity u is given by;

How high would the ball reach if the initial speed becomes 2U?

If a ball thrown vertically upwards with initial speed of “u” reached “h” meters, how high would the ball reach if the initial speed becomes 2u (in terms of h)? If you want quick answer then it is 2h in terms of 2u.

How do you find the time when a ball is projected upward?

Let the point from where the ball is projected upward be taken a origin of coordinate system and the upward direction as positive and downward direction as negative. We can get the time by using the relation: s = u t + ½ a t², where s = displacement. In our case since the ball returns to the starting point the displacement s is zero.