What is the last digit of 3 100?

What is the last digit of 3 100?

Brute-force answer: 3100=515,377,520,732,011,331,036,461,129,765,621,272,702,107,522,001. and since 10 is a divisor of 3100−1, the last digit of 3100 is 1.

How do you find the last digit of 2 100?

so last digit of 2^100=6. Originally Answered: What will be the last digit of 2^100? and so on. 2^100 ends with the same digit as 2^4 which is 6.

What is the unit digit of 2 Power 100?

Hence the units digit of 2^100= 6.

What is the last digit of 3 45?

There is a clear pattern that it cycles every 20th power (note that the last digit cycles every 4th power: 1-3-9-7…). Therefore the last two digits of 345 are the same as for 325 and for 35=243, i.e. 43.

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What is the last digit of 81 when divided by 4?

Hint: 3 4 ≡ 1 mod 10. If a number has 1 as its last digit , any power of such number will have 1 as its last digit. So last digit of 81 is 1. according as the exponent leaves a remainder 1, 2, 3, or 0, respectively, when divided by 4. For example, and so forth. Since 100 ≡ 0 ( mod 4), the final answer is 1.

How to find the last two digits of \\:\\31^{76}}\\)?

Say we need to find the last two digits of \\({31^{76}}\\). The trick to finding the second last digit of any number ending with 1 is the UNIT DIGIT of the product of the unit digit of the power and the ten’s digit of the base. It is clear that the unit digit of the given number is 1 and we have to identify the ten’s place digit of the same.

What is the last digit of 3 20 m mod 100?

So 3 20 m ≡ 1 mod 100 so the last two digits of 3 100 are 01. so the last digit is 1. In fact it’s easy to see from this that the last two digits are 01, and not too hard to see that the last three digits are 001 (because the first three terms of the expansion are 1 − 500 + 62500 = 62001 ).

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How to find the last two digits of 7964 with unit digit?

Convert the number by repeatedly squaring until we get the unit digit as 1, and then applying the trick of finding the last two digits of number with unit digit 1 as explained above. Therefore, the last two digits of 7964 ≡ 79 64 ≡ last two digits of (792)32 ≡ ( 79 2) 32 ≡ 4132 ≡ 81 41 32 ≡ 81