What is the probability that a number being picked from 1 to 100 is divisible by 4 but not by 8?

Probability of chosen a number is not divisible by 8 = 43/49.

What is the probability that chosen number is divisible by 6 or 8?

Then, the probability that the integer chosen is divisible by 6 or 8, is. A∩B be the event such that an integer is divisible by both 6 and 8, There are 8 integers from the first 200 numbers, which are divisible by both 6 and 8. P(AUB) = 50/200 = ¼.

What are integers numbers from 1 to 100?

The first 100 whole numbers are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25,26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 60, 61, 62, 63, 64, 65, 66, 67, 68, 69, 70, 71, 72, 73, 74.

What is the probability that a number selected at random from the first 100 positive integers is exactly divisible by 6 or 8?

Expert Answers For instance, 30 divided by 8 is 3.75. 6 divided by 8 is . 75. This gives the probability that an integer chosen from the set of integers from 1 to 100 that is divisible by 6 or 8 as 0.24.

What are the numbers that are divisible by 6?

A number is divisible by 6 if it is divisible by 2 and 3 both. Consider the following numbers which are divisible by 6, using the test of divisibility by 6: 42, 144, 180, 258, 156. [We know the rules of divisibility by 2, if the unit’s place of the number is either 0 or multiple of 2]. 42 is divisible by 2.

What is the integers from 1 to 100?

What is sum of the integers from 1 to 100?

5050
The sum of all natural numbers from 1 to 100 is 5050.

What is the probability that the number chosen is neither divisible?

Hence, numbers which are not divisible by 4 or 6 = 100-33 = 67 Therefore the probability that the number chosen, is neither divisible by 4 nor divisible by 6 = 67/100 = 0.67 Notice that the value of the Probability of a random event always lies between 0 and 1.

How many integers are divisible by both 6 and 8?

The number of integers divisible by both 6 and 8 is 4. The number of integers in the set of 100 numbers that meets the given criterion is 16 + 12 – 4 = 24

How do you find the least integer divisible by 5?

So n > ln ⁡ 2 ln ⁡ 5 − ln ⁡ 4. You can evaluate this with your calculator, so the least integer greater than that is the result. Obviously, the more certain you want to be of picking a number divisible by 5, the more times you have to pick a number. An integer is chosen from the first 200 positive integers.

How many numbers are divisible by 6 from 1 to 200?

We know that 198 is divisible by 6 and the next number divisible by 6 is 204 > 200. The nth number divisible by 6 is 6n so 198 is 33rd number divisible by 6. So there are 33 numbers divisible by 6 from 1 to 200. The same way we have 200 divisible by 8 and 200 is the 200/8 = 25th number divisible by 8 from 1 to 200.