What is the ratio of inradius and circumradius of an equilateral triangle?

NOTE: The ratio of circumradius to inradius in an equilateral triangle is 2:1 or (R = 2r).

What is the circum radius of an equilateral triangle whose side is 9 cm?

⇒OB=4.5√3/2=91.732=5.196. Therefore, the radius of the circle = OB = 5.196cm. Note: In this question, you should know about the circumcircle of the triangle. It is a triangle whose centre is the point of intersection of the perpendicular bisectors of the sides of the triangle and touches the vertices of the triangle.

What is the formula for circumradius of an equilateral triangle?

The radius of a circumcircle of an equilateral triangle is equal to (a / √3), where ‘a’ is the length of the side of equilateral triangle.

What is the circum radius of an equilateral triangle of side 8cm?

Hence , the circumradius is 8/√3 cm.

What is the ratio of the area of Circumcircle of equilateral triangle to the area of the square with the same side length as equilateral triangle?

∴ Required ratio = πa23a2 π a 2 3 a 2 = π3 = π : 3.

What is in radius of a triangle?

The incircle is the largest circle that can fit inside of a triangle. The radius of this circle is known as the inradius. Inradius can be calculated with the following equation: r=As Where A is the area of the triangle, and s is the semi-perimeter of the triangle, or one-half of the perimeter.

What is the circumference of an equilateral triangle if the inradius is 7cm?

Question 6: If the inradius of an equilateral triangle is 7 cm, then the circumference of the circumcircle of the triangle will be (Take ∏ = 22/7) The ratio of circumradius (R) & inradius (r) in an equilateral triangle is 2:1, so R/ r = 2:1. Here r = 7 cm so R = 2r = 2×7 = 14 cm.

What is the ratio of circumradius to in radius?

Circumradius (R) Circumradius is defined as the radius of that circle which circumscribes (surrounds) the triangle. As shown in the above figure, the circle with centre O passes through the three vertices of the triangle ABC. NOTE: The ratio of circumradius to inradius in an equilateral triangle is 2:1 or (R = 2r).

What is the base of a 9 cm equilateral triangle?

If the height of an equilateral triangle is 9 cm then the base = 2*9*cot 60 = 10.39230485 cm. The area of the equilateral triangle = 9 * 10.39230485/2 = 46.7653718 sq cm.

What is the area of the circumcircle of an equilateral triangle?

The ratio of circumradius (R) & inradius (r) in an equilateral triangle is 2:1, so R/ r = 2:1. Here R = 14 cm. So r = R/2 = 14/2 = 7 cm. Area of incircle = ∏r 2 = 22/7 X 7 2 = 154 cm 2 Question 6: If the inradius of an equilateral triangle is 7 cm, then the circumference of the circumcircle of the triangle will be (Take ∏ = 22/7)