What is the ratio of the mass of methane to the mass of oxygen in this reaction?

For example, in the combustion of methane (CH4), equation 1, the stoichiometric ratios are 1:2:1:2, methane to oxygen to carbon dioxide to water, respectively.

What is the ratio of volumes of methane oxygen and carbon dioxide in combustion reaction of methane?

You have a 1:2 mole ratio between methane and oxygen, which means that you will also have a 1:2 volume ratio between the two gases.

What is the total no of electrons present in 1.6 g of methane?

16 grams of CH4 contains 10*6.023*10^23 electrons = 6.023*10^24 electrons. And 1 mol methane present in 6.022*10^23 according avogrado constant.. So and total electron in methane is 6and 4 so it’s total is 10 so.

What is the ratio of CH4 to O2?

one to two
So the molar ratio of methane to oxygen is one to two, which means that for every one mole of methane, two moles of oxygen is needed to react with it.

What happens when methane reacts with steam?

In steam-methane reforming, methane reacts with steam under 3–25 bar pressure (1 bar = 14.5 psi) in the presence of a catalyst to produce hydrogen, carbon monoxide, and a relatively small amount of carbon dioxide.

What is the ratio of masses of H2 and o2 in H2O?

1 : 2. Hint: Consider the number of hydrogen and oxygen atoms that constitute one molecule of water and also the atomic masses of hydrogen and oxygen. We know that the molecular formula of water is H2O. It has 2 hydrogen atoms and 1 oxygen atom.

What happens when CH4 reacts with O2?

The reaction between the emission of CH4 gas and oxygen (O2) will form carbon dioxide (CO2) and water content (H2O).

How many total no of electrons present in 8g of methane?

Grade 8. There are 4 H atoms and 1 C atom. molecules. Each molecule contains 10 electrons.

What is the ratio of volume of oxygen hydrogen and methane?

Equal masses of oxygen, hydrogen and methane are taken in a container in identical conditions. Find the ratio of the volumes of the gases. 1. Oxygen = 32 2.

What is the volume ratio of 32g of O2 H2 and CH4?

Let us consider 32 g of each O2, H2 and CH4 are in a container at identical conditions. It’s volume ratio will be the Molar ratio. Then volume of ratio of O2 : H2: CH4 I have the taken equal Mass to be 32 g, because it is the LCM OF THE MOLECULAR MASS OF O2, H2 and CH4.

What fraction of the container does 10 grams of CH4 occupy?

So if for arguments sake we have 10 grams of each gas in the vessel ( ie equal masses ); 10 grams CH4 will occupy 10÷0.7168 = 13.950 fraction of the container. If we simplify this ratio into the lowest common denominator ( ie. smallest numbers ) : 10 grams CH4 will occupy 10÷0.7168 = 13.950 fraction of the container.

What happens when 10ml of O2 reacts with 20ml of H2?

So 10 ml of O2 will react with 20 ml of H2 to produce water. The remaining (50–20)=30 ml of Hydrogen will remain unreacted. {The mass of water formed= 20/22400 x 18= 0.01607 g or =0.01607 ml. This volume will be negligible when compared to 30 ml of Hydrogen gas.