Table of Contents
- 1 What is the speed of the train the train crosses a signal pole in 18 seconds?
- 2 What is the speed of a train of 80 Metre long train crosses a railway station platform of 120 Metres length in 20 seconds?
- 3 What is the speed of train the train crosses?
- 4 How long will a train 120m long take to clear a platform 130m long if its speed is 50 km/hr *?
- 5 What is the length of a running train crossing another 180?
- 6 What is the speed of the train when it crosses the platform?
- 7 What is the speed of the train with a uniform speed?
What is the speed of the train the train crosses a signal pole in 18 seconds?
Explanation: Speed = Length of the train / Time taken to cross the pole =28018 m/s =1409 m/s. ∴ I alone gives the answer. ⇒ Speed =(280+p)45 m/s.
What is the speed of a train of 80 Metre long train crosses a railway station platform of 120 Metres length in 20 seconds?
=20m/s. Then speed in km/hr=20×18/5=72km/hr. Hence option (a) 72km/hr is correct answer.
How much time would a 180 m long train would take to pass a 320 m long platform when its speed is 60 kmph?
Q1. A 220 meters long train crosses an electric pole in 11 seconds and crosses another train of equal length running in the opposite direction in 8 seconds. What is the speed of the second train? Q2.
What is the length of train 1 The train crosses a pole in 18 seconds 2 The train crosses a signal pole in 18 seconds 3 speed of train is 60 kmph?
Length of train = 330 m. m/sec. m/sec. Correct answer is (D)….Exercise :: Problems on Trains – Data Sufficiency 2.
What is the speed of the train? | |
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I. | The train crosses a signal pole in 18 seconds. |
II. | The train crosses a platform of equal length in 36 seconds. |
III. | Length of the train is 330 metres. |
What is the speed of train the train crosses?
The relative speed of the two trains was 150 kmph. II. The trains took 9 seconds to cross each other. E….Exercise :: Problems on Trains – Data Sufficiency 1.
What is the length of a running train? | |
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I. | The train crosses a man in 9 seconds. |
II. | The train crosses a 240 metre long platform in 24 seconds. |
How long will a train 120m long take to clear a platform 130m long if its speed is 50 km/hr *?
Therefore, total distance = 120+130=250m = 0.25km. Speed of the train = 50 km/h. Time = Distance / Speed. So, time = 0.25 /50 hours = 1/200 hours.
What is the time in seconds by a 180 m train Travelling at a speed of 270 kmph to fully cross milestone?
Given D1=180m,D2=270m ;T=10.8 sec;S1=60kmph. Answer: Let, the speed of 2nd train be x m/s. ATP, (270+180)/(60*5/18 + x) = 10.8 .
What is the length of the train data sufficiency?
Exercise :: Problems on Trains – Data Sufficiency 1
What is the length of a running train crossing another 180 metre long train running in the opposite direction? | |
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I. | The relative speed of the two trains was 150 kmph. |
II. | The trains took 9 seconds to cross each other. |
What is the length of a running train crossing another 180?
Let the two trains of length a metres and b metres be moving in opposite directions at u m/s and v m/s. sec. m/sec. a = (375 – 180) = 195 m.
What is the speed of the train when it crosses the platform?
A 160 meter long train running at a speed of 90 km/h crosses a platform in 18 seconds. What is the length of the platform in meters? Please log in or register to add a comment.
How long does it take for a 180m long train to cross?
A 180 m long train crosses a man standing on the platform in 6 seconds. What is the speed of the train?
How long does it take to cross a platform?
A train, with a uniform speed, crosses a platform, 162 metre long, in 18 seconds and another platform, 120 metre long, in 15 seconds. The speed of the train is – Competoid.com A train, with a uniform speed, crosses a platform, 162 metre long, in 18 seconds and another platform, 120 metre long, in 15 seconds.
What is the speed of the train with a uniform speed?
A train, with a uniform speed, crosses a platform, 162 metre long, in 18 seconds and another platform, 120 metre long, in 15 seconds. The speed of the train is l e n g t h = 18 x − 162 …..