When a ball is thrown up vertically upwards?

When a ball is thrown up vertically with velocity vo​ it reaches a maximum height of h. If one wishes to triple the maximum height then the ball should be thrown with velocity.

Do this sum a ball thrown up vertically upward and return to the tower after 6 Second find a the velocity with which it was thrown up maximum height it reached?

(a) Time of ascent is equal to the time of descent. The ball takes a total of 6 s for its upward and downward journey. Hence, it has taken 3 s to attain the maximum height. Hence, the ball was thrown upwards with a velocity of 29.4 m s−1.

What will be the position of ball after 6 seconds?

Answer: Time to reach Maximum height, t = 6/2 = 3 s. Since the ball is thrown upwards, the acceleration is negative.

What is the velocity after 6s?

Hence, the velocity of an object after 6s is $(9 \hat{i} – 12 \hat{j})$. So, the correct answer is option A i.e. $(9 \hat{i} -12 \hat{j})$. So, the correct answer is “Option A”. Hence, the velocity of an object after 6s is $(9 \hat{i} – 12 \hat{j})$.

When a ball is thrown vertically upward it returns to the thrower?

A ball thrown vertically upward returns to the thrower after 6 s. The ball is 5 m below the highest point at t = 2 s. The time at which the body will be at same position, (take g = 10 m/s 2 ).

How long does it take a ball to reach its maximum velocity?

Then we’ll integrate again with respect to time to get the distance. Since the ball is thrown and lands at the exact same height and it takes 6 seconds to do so, it must take half of that time, or 3 seconds, to reach its maximum height (conservation of energy). At that time the velocity will be 0.

What is the acceleration of the ball after two second?

The acceleration on the ball after two second ( or for that matter any time thereafter, till it comes back to earth) would be – 9.81 m/s²., the minus sign merely means it is directed downwards towards the earth. A ball is thrown vertically upwards from the ground with a velocity of 30 m/s.

What is the maximum height of the ball after 4 s?

The maximum height reached by the ball (c). After 3 second, it starts to fall down. Hence after 4 s, the ball is at a height of 40 m above the ground. Was this answer helpful?