Which ball will reach the floor first?

In other words, if two objects are the same size but one is heavier, the heavier one has greater density than the lighter object. Therefore, when both objects are dropped from the same height and at the same time, the heavier object should hit the ground before the lighter one.

Which of the two balls reach the ground first?

Both balls reach the ground at the same time. Ball 2 reaches the ground first, because it has the shorter distance to travel. Ball 1 reaches the ground first, since it is moving at the top of the trajectory, while ball 2 is dropped from rest.

What will reach the ground first?

Heaver objects fall faster. If you drop a heavy and light object together, the heavy one will get to the ground first. This is trick question. I remember in physics that everything falls the same.

Which bowling ball will fall faster?

The laws of gravity dictate that a bowling ball will always drop faster than a feather. But try the same experiment in a giant vacuum and that’s when it gets interesting.

Which of the papers hit the ground first Why?

The reason the crumpled paper hits the ground first is because of air resistance. A crumpled piece of paper has less surface area than an piece of paper that is not crumpled. More surface area means more air resistance.

Why do two objects of different weights fall at the same speed?

Heavier things have a greater gravitational force AND heavier things have a lower acceleration. It turns out that these two effects exactly cancel to make falling objects have the same acceleration regardless of mass.

What is the initial speed of each ball thrown from the tower?

Two balls X and Y are thrown from top of tower one vertically upward and other vertically downward with same speed. If times taken by them to reach the ground are 6s and 2s respectively, then the height of the tower and initial speed of each ball are (g = 10m/s2)

What is the initial velocity of a ball dropped from a building?

A ball (A) is dropped from a 100 m tall building and another one (B) thrown upward. Assuming ball is dropped at rest and another ball is thrwon by velocity u m/s. Suppose they meet after time t, Distance travelled in meters by ball A , s= ut+1/2gt^2 , initial velocity of ball is zero hence ,S (ball A) = 1/2 at^2

What is the total distance covered by Ball 1?

If the distance covered by ball 2 is x, then the distance covered by ball 1 will be 100−x, Since the total hieght is 100m. Since acceleration is constant, T herefore we can apply equations of motion for both balls (considering Positive Downwards). 10t 2 .

What happens from the top of a tower 100m in height?

>> From the top of a tower 100… From the top of a tower 100m in height a ball is dropped and at the same time another ball is projected vertically upwards from the ground with velocity of 25ms −1. Find when and where the two balls will meet.