Which is the equation of the line perpendicular to 4x − 5y 17 that passes through the point 5 2 )?

y=4−5x+215.

Which of the following is the equation of the line that passes through the points (- 1/3 and (- 5 1?

Answer: The Equation of the Line Passing through the given Points (-1, 5), (1, 3) is x + y = 4.

What is the equation of a line that passes through the point 1 and 3 and negative 2 and 5?

y = 2x + 1 this is slope-intercept form. 2x – y = -1 this is standard form.

What is the equation of the line that passes through the point (- 3 4 and has a slope of 11?

Answer: y = 5x – 11 is the equation of the required line.

Which of the following is the equation of a straight line that passes through point 4 3 and is perpendicular?

Thus, the equation of the line perpendicular to the x-axis and passing through (4, 3) is x = 4. Hence, the required lines are x = 4 and y = 3.

What is an equation of the line that passes through the points (- 5 1 and 5 3 )?

How do you find the equation of a perpendicular line?

Perpendicular lines have opposite-reciprocal slopes, so the slope of the line we want to find is 1/2. Plugging in the point given into the equation y = 1/2x + b and solving for b, we get b = 6. Thus, the equation of the line is y = ½x + 6. Rearranged, it is –x/2 + y = 6.

How to find the slope of a perpendicular line in slope intercept form?

First, put the equation of the line given into slope-intercept form by solving for y. You get y = -2 x +5, so the slope is –2. Perpendicular lines have opposite-reciprocal slopes, so the slope of the line we want to find is 1/2. Plugging in the point given into the equation y = 1/2 x + b and solving for b, we get b = 6.

What is the slope of the line parallel to line 3x + 4Y?

Given equation of line 3x + 4y = 7 .. (iii) The slope of the line parallel to line (iii) is -¾. (since parallel lines have equal slopes) Hence option (1) is the answer. Was this answer helpful? Thank you.

What is the definition of a perpendicular line?

The definition of a perpendicular line is one that has a negative, reciprocal slope to another. For this particular problem, we must first manipulate our initial equation into a more easily recognizable and useful form: slope-intercept form or. According to our formula, our slope for the original line is.