Why do we put address in the scanf function and why not in printf?

scanf needs to write on a memory location. It needs an address where it can write a value. This is done through the & operator. printf just needs the values to output them and hence it doesn’t need a memory location reference.

Why does scanf take address?

The reason is, scanf() needs to modify values of a and b and but they are local to scanf(). So in order to reflect changes in the variable a and b of the main function, we need to pass addresses of them. We cannot simply pass them by value.

Can we use printf in scanf?

scanf() reads the values supplied from standard input and return number of values successfully read from standard input (keyboard). In C, printf() returns the number of characters successfully written on the output and scanf() returns number of items successfully read.

Why is it necessary to pass in and not in itself to scanf?

When passing stuff to scanf(), you need to pass in a pointer to the variable, not the variable itself. The & means “Don’t take the variable, take the place in memory where this variable is stored.” It’s a little complicated, but it’s necessary so that C can change the value of the variable.

How can printf () and scanf () take multiple arguments?

If you have multiple format specifiers within the string argument of scanf, you can input multiple values. All you need to do is to separate each format specifier with a DELIMITER – a string that separates variables.

Where can we not use &( address operator in C?

It cannot be used on constants. It cannot be used on variable which are declared using register storage class.

What is difference between printf and scanf?

It is there to take an input, usually from the keyboard if that is the default device. So, the main difference is that one is for reading an input (scanf) while the other is for providing an output from the program (printf).

What is actually passed to printf and scanf functions?

19) What is actually passed to PRINTF or SCANF functions.? Explanation: printf(“Hello”) takes the address of “Hello” and processes till it reaches NULL or \0.

Is address operator used in scanf () statement to read an array Why?

Why “&” is not used for strings in scanf() function? Below is syntax of Scanf. In case of a string (character array), the variable itself points to the first element of the array in question. Thus, there is no need to use the ‘&’ operator to pass the address.

Why scanf doesn’t take the address of operator (&) in C?

Because C only has “pass-by-value” parameters, so to pass a ‘variable’ to put a value into, you have to pass its address (or a pointer to the variable). scanf does not take “the address of operator (&)”.

Why do we use ‘&’ in case if scanf function?

Why there is need of using ‘&’ in case if scanf function while not in case of printf function. As a and b above are two variable and each has their own address assigned but instead of a and b, we send the address of a and b respectively. The reason is, scanf () needs to modify values of a and b and but they are local to scanf ().

Is it necessary to send the variable addresses in printf function?

But in case of printf function as we are only going to print the values of the variables in output console, there are no changes going to be made in variable a and b’s values. So it is not required to send their addresses.

What is an example of scanf in C++?

Examples: scanf (“\%d \%d”, &a, &b); printf (“\%d \%d”, a, b); As a and b above are two variable and each has their own address assigned but instead of a and b, we send the address of a and b respectively. The reason is, scanf () needs to modify values of a and b and but they are local to scanf ().